汇编实验七（王爽）

最开始写的有很多循环的（容易理解，但复杂性高）

assume cs:code,ss:stack

data segment
    db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
    db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
    db '1993','1994','1995'

    dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
    dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
    dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
    dw 11542,14430,15257,17800
data ends

table segment
    db 21 dup('year summ ne ?? ')
table ends

stack segment
    dw 0,0,0,0,0,0,0,0
stack ends

code segment
start: mov ax,data
       mov ds,ax
       mov ax,table
       mov es,ax
       mov ax,stack
       mov ss,ax
       mov sp,10h
       mov bx,0
       mov bp,0
       mov cx,21
     s:push cx
       mov si,0
       mov cx,4
    s0:mov al,[bx+si]
       mov es:[bp+si],al
       inc si
       loop s0
       mov al,' '
       mov es:[bp+si+1],al

       add bx,4
       add bp,16
       pop cx
       loop s

        mov bx,84
        mov bp,5
        mov cx,21
     s1:mov ax,ds:[bx]
        mov dx,ds:[bx+2]
        mov es:[bp],ax
        mov es:[bp+2],dx
       mov al,' '
       mov es:[bp+4],al        

        add bx,4
        add bp,16
        loop s1

        mov bx,168
        mov bp,10
        mov cx,21
     s2:mov ax,ds:[bx]
        mov es:[bp],ax
        mov al,' '
        mov es:[bp+2],ax

        add bx,2
        add bp,16
        loop s2

        mov bx,84
        mov si,168
        mov bp,13
        mov cx,21
     s3:mov ax,ds:[bx]
        mov dx,ds:[bx+2]
        div word ptr ds:[si]
        mov es:[bp],ax
        mov al,' '
        mov es:[bp+2],al

        add si,2
        add bx,4
        add bp,16
        loop s3

        mov ax,4c00h
        int 21h

code ends

end start

运行结果如下

 修改后，只剩下一个循环，代码复制性减少了很多

assume cs:code,ss:stack

data segment
    db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
    db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
    db '1993','1994','1995'

    dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
    dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
    dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
    dw 11542,14430,15257,17800
data ends

table segment
    db 21 dup('year summ ne ?? ')
table ends

stack segment
    dw 0,0,0,0,0,0,0,0
stack ends

code segment
start: mov ax,data
       mov ds,ax
       mov ax,table
       mov es,ax
       mov ax,stack
       mov ss,ax
       mov sp,10h
       mov bx,0
       mov bp,0
       mov si,0
       mov cx,21

     s:mov ax,ds:[bx]
       mov es:[bp],ax
       mov ax,ds:[bx+2]
       mov es:[bp+2],ax
       mov al,' '
       mov es:[bp+4],al

       
        mov ax,ds:[bx+84]
        mov dx,ds:[bx+84+2]
        mov es:[bp+5],ax
        mov es:[bp+7],dx
        mov al,' '
        mov es:[bp+9],al        

      
        mov ax,ds:[si+168]
        mov es:[bp+10],ax
        mov al,' '
        mov es:[bp+12],ax

       
        mov ax,ds:[bx+84]
        mov dx,ds:[bx+84+2]
        div word ptr ds:[si+168]
        mov es:[bp+13],ax
        mov al,' '
        mov es:[bp+15],al

        add bp,16      //->用来表示table表内的内存偏移地址（用来控制table表的行数，以及间接地表示内存偏移地址）
        add bx,4       //->用来表示dd性与字符串型数据的偏移地址（每读取一段数据后，需移动四个字节）
        add si,2       //->>用来表示dw性数据的偏移地址(每读取一段数据后，只需移动两个字节)
        loop s

        mov ax,4c00h
        int 21h

code ends

end start

运行结果如下：