• URAL1146——DP——Maximum Sum


    Description

    Given a 2-dimensional array of positive and negative integers, find the sub-rectangle with the largest sum. The sum of a rectangle is the sum of all the elements in that rectangle. In this problem the sub-rectangle with the largest sum is referred to as the maximal sub-rectangle. A sub-rectangle is any contiguous sub-array of size 1 × 1 or greater located within the whole array.
    As an example, the maximal sub-rectangle of the array:
    0 −2 −7 0
    9 2 −6 2
    −4 1 −4 1
    −1 8 0 −2
    is in the lower-left-hand corner and has the sum of 15.

    Input

    The input consists of an N ×  N array of integers. The input begins with a single positive integer N on a line by itself indicating the size of the square two dimensional array. This is followed by N 2 integers separated by white-space (newlines and spaces). These N 2 integers make up the array in row-major order (i.e., all numbers on the first row, left-to-right, then all numbers on the second row, left-to-right, etc.). N may be as large as 100. The numbers in the array will be in the range [−127, 127].

    Output

    The output is the sum of the maximal sub-rectangle.

    Sample Input

    inputoutput
    4
    0 -2 -7 0
    9 2 -6 2
    -4 1 -4 1
    -1 8 0 -2
    
    15
    
     大意:问你最大的矩阵和,坑死我了WA了n发。。原来做的方法错了。没有考虑当答案为负值的时候
    dp[i][j][k]表示i行j列从k个元素开始往前的和,三重循环保证所有情况都遍历到
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    int dp[150][150][150];
    int a[150][150];
    const int inf = 0x3f3f3f3f;
    int main()
    {
        int n;
        while(~scanf("%d",&n)){
            for(int i = 1; i <= n ; i++)
                for(int j = 1; j <= n ;j++)
                    scanf("%d",&a[i][j]);
            memset(dp,0,sizeof(dp));
            int ans = -inf;
            for(int i = 1; i <= n ; i++){
                for(int j = 1; j <= n ;j++){
                    int sum = 0;
                    for(int k = j; k >= 1; k--){
                        sum += a[i][k];
                        dp[i][j][k] = max(sum + dp[i-1][j][k],sum);
                        ans = max(ans,dp[i][j][k]);
                    }
                }
            }
            printf("%d
    ",ans);
        }
        return 0;
    }
    

    错误代码也来一发....祭奠我8个WA一个CE..

    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    int main()
    {
        int a[150][150];
        int n,m;
        scanf("%d",&n);
        for(int i = 1; i <= n ;i++){
            for(int j = 1; j <= n ;j++){
             scanf("%d",&m);
             a[i][j] = a[i-1][j] + m;
            }
        }
    
        int max1 = 0;
        int sum;
        for(int i = 1; i <= n ;i++){
            for(int j = i+1 ; j<= n ;j++){
                int sum = 0;
                for(int k = 1; k <= n;k++){
                  int temp = a[j][k] - a[i][k];
                   sum += temp;
                  if(sum < 0) sum = 0;
                  if(sum  > max1) max1 = sum;
                }
            }
        }
        printf("%d",max1);
       return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/zero-begin/p/4483271.html
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