• Happy Three Friends


    Happy Three Friends


    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
    Total Submission(s): 0    Accepted Submission(s): 0


    Problem Description
    Dong-hao , Grandpa Shawn , Beautful-leg Mzry are good friends. One day , they want to play a game.

    There are 6 numbers on the table.

    Firstly , Dong-hao can change the order of 6 numbers.

    Secondly , Grandpa Shawn take the first one and the last one , sum them up as his scores.

    Thirdly , Beautiful-leg Mzry take any of 3 numbers from the last 4 numbers , and sum them up as his scores.

    Finally , if Grandpa Shawn's score is larger than Beautiful-leg Mzry's , Granpa Shawn wins!

    If Grandpa Shawn's score is smaller than Beautiful-leg Mzry's , Granpa Shawn loses.

    If the scores are equal , there is a tie.

    Nowadays , it's really sad that Grandpa Shawn loses his love. So Dong-hao wants him to win(not even tie). You have to tell Dong-hao whether he can achieve his goal.
     
    Input
    There is a number T shows there are T test cases below. ( T <= 50)

    For each test case , there are 6 numbers Ai ( 1 <= Ai <= 100 ).
     
    Output
    If Dong-hao can achieve his goal , output "Grandpa Shawn is the Winner!"
    If he can not , output "What a sad story!"
     
    Sample Input
    3
    1 2 3 3 2 2
    2 2 2 2 2 2
    1 2 2 2 3 4
     
    Sample Output
    What a sad story!
    What a sad story!
    Grandpa Shawn is the Winner!
     
    Hint
    For the first test case , {3 , 1 , 2 , 2 , 2 , 3} Grandpa Shawn can take 6 at most . But Beautiful-leg Mzry can take 6 too. So there is a tie. For the second test cases , Grandpa Shawn loses. For the last one , Dong-hao can arrange the numbers as {3 , 2 , 2 , 2 , 1 , 4} , Grandpa Shawn can take 7 , but Beautiful-leg Mzry can take 6 at most. So Grandpa Shawn Wins!
     
    解题:( ̄o ̄) . z Z   水
     
     1 #include <iostream>
     2 #include <cstdio>
     3 #include <cstring>
     4 #include <cmath>
     5 #include <algorithm>
     6 #include <climits>
     7 #include <vector>
     8 #include <queue>
     9 #include <cstdlib>
    10 #include <string>
    11 #include <set>
    12 #include <stack>
    13 #define LL long long
    14 #define INF 0x3f3f3f3f
    15 using namespace std;
    16 int d[8],n;
    17 int main() {
    18     int t,i,j,grapa,mzry;
    19     scanf("%d",&t);
    20     while(t--){
    21         for(i = 0;i < 6; i++)
    22             scanf("%d",d+i);
    23         sort(d,d+6);
    24         grapa = d[5]+d[4];
    25         mzry = d[3]+d[2]+d[1];
    26         if(grapa > mzry){
    27             puts("Grandpa Shawn is the Winner!");
    28         }else puts("What a sad story!");
    29     }
    30     return 0;
    31 }
    View Code
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  • 原文地址:https://www.cnblogs.com/crackpotisback/p/3903610.html
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