Access the value of a member expression
解答1
You can compile and invoke a lambda expression whose body is the member access:
private object GetValue(MemberExpression member)
{
var objectMember = Expression.Convert(member, typeof(object));
var getterLambda = Expression.Lambda<Func<object>>(objectMember);
var getter = getterLambda.Compile();
return getter();
}
Local evaluation is a common technique when parsing expression trees. LINQ to SQL does this exact thing in quite a few places.
解答2
MemberExpression right = (MemberExpression)((BinaryExpression)p.Body).Right;
Expression.Lambda(right).Compile().DynamicInvoke();
会有同样的问题
尝试gist
https://gist.github.com/jcansdale/3d4b860188723ea346621b1c51fd8461#file-expressionutilities-cs-L13
UKERecognition.Infrastructure.Exceptions.UIException: UserInterface ---> System.Exception: Couldn't evaluate Expression without compiling: l
private static object GetMemberValue(MemberExpression expression) { if (expression == null) return null; var field = expression.Member as FieldInfo; if (field != null) { var constValue = GetConstantValue(expression.Expression); return field.GetValue(constValue); } var property = expression.Member as PropertyInfo; if (property == null) return null; var value = GetMemberValue(expression.Expression as MemberExpression); return property.GetValue(value); } private static object GetConstantValue(Expression expression) { var constantExpression = expression as ConstantExpression; if (constantExpression == null) return null; return constantExpression.Value; }
System.Reflection.TargetException: Non-static method requires a target.
at System.Reflection.RuntimeMethodInfo.CheckConsistency(Object target)
at System.Reflection.RuntimeMethodInfo.InvokeArgumentsCheck(Object obj, BindingFlags invokeAttr, Binder binder, Object[] parameters, CultureInfo culture)
at System.Reflection.RuntimeMethodInfo.Invoke(Object obj, BindingFlags invokeAttr, Binder binder, Object[] parameters, CultureInfo culture)
at System.Reflection.RuntimePropertyInfo.GetValue(Object obj, Object[] index)
at LISA.Custom.Infrastructure.LisaExpressionVisitor`1.GetMemberValue(MemberExpression expression) in