• DB2行转列(多维度)


    多维度下进行行列转换,下面的行列转换时根据客户,所属银行机构进行的行列转换。

    -----------------建表
    CREATE TABLE CUST_BANK_INFO
    (
     CUST_ID VARCHAR(10),
     CUST_NAME VARCHAR(100),
     BANK_NO VARCHAR(100),
     BANK VARCHAR(100),
     MONEY_TYPE_NO VARCHAR(100),
     MONEY_TYPE VARCHAR(100),
     MONEY INT
    );
    
    INSERT INTO CUST_BANK_INFO VALUES('C001','允贤','B01','中国银行','MT01','理财',10000);
    INSERT INTO CUST_BANK_INFO VALUES('C002','李四','B01','中国银行','MT02','贷款',20390);
    INSERT INTO CUST_BANK_INFO VALUES('C003','王五','B01','中国银行','MT03','存款',29301);
    INSERT INTO CUST_BANK_INFO VALUES('C004','陈六','B01','中国银行','MT04','教育储蓄',10000);
    INSERT INTO CUST_BANK_INFO VALUES('C001','允贤','B02','中国银行','MT01','理财',20000);
    INSERT INTO CUST_BANK_INFO VALUES('C005','JACK','B02','工商银行','MT05','理财',10001);
    INSERT INTO CUST_BANK_INFO VALUES('C006','王三','B02','工商银行','MT06','贷款',10002);
    INSERT INTO CUST_BANK_INFO VALUES('C007','刘六','B02','工商银行','MT07','存款',10003);
    INSERT INTO CUST_BANK_INFO VALUES('C008','郑七','B02','工商银行','MT08','教育储蓄',10004);
    
    SELECT * FROM CUST_BANK_INFO
    
    
    查询结果如下:

    --DELETE FROM CUST_BANK_INFO
    DROP TABLE Mapping;
    CREATE TABLE Mapping
    (
     CN_NAME VARCHAR(100),
     Code_L  VARCHAR(10),
     Code_N  VARCHAR(10)
    )
    INSERT INTO Mapping values('理财','MT01','BANK_01');
    INSERT INTO Mapping values('理财','MT05','BANK_01');
    INSERT INTO Mapping values('贷款','MT02','BANK_02');
    INSERT INTO Mapping values('贷款','MT06','BANK_02');
    INSERT INTO Mapping values('存款','MT03','BANK_03');
    INSERT INTO Mapping values('存款','MT07','BANK_03');
    INSERT INTO Mapping values('教育储蓄','MT04','BANK_04');
    INSERT INTO Mapping values('教育储蓄','MT08','BANK_04');
    
    
        
    SELECT CUST_ID,
           CUST_NAME,
           BANK_NO,
           BANK,
    max(CASE WHEN B.Code_N='BANK_01' THEN MONEY ELSE '0' END) AS 理财,
    max(CASE WHEN B.Code_N='BANK_02' THEN MONEY ELSE '0' END) AS 贷款,
    max(CASE WHEN B.Code_N='BANK_03' THEN MONEY ELSE '0' END) AS 存款,
    max(CASE WHEN B.Code_N='BANK_04' THEN MONEY ELSE '0' END) AS 教育储蓄
    FROM CUST_BANK_INFO A
    LEFT JOIN MAPPING B ON A.MONEY_TYPE_NO=B.Code_L
    group by CUST_ID,CUST_NAME,BANK,BANK_NO

    查询结果如下:

  • 相关阅读:
    常用的逻辑控制器。
    map集合迭代。
    [译]如何在.NET Core中使用System.Drawing?
    使用.Net Core 2.1开发Captcha图片验证码服务
    ife 零基础学院 day 2
    ife 零基础学院 day 1
    Visual Studio 2017
    Visual Studio 2017
    在Windows 10上利用seafile搭建个人云服务
    Web网站配置Gzip,压缩js css文件
  • 原文地址:https://www.cnblogs.com/OliverQin/p/5344659.html
Copyright © 2020-2023  润新知