class Solution { public: int minDistance(string word1, string word2) { // Start typing your C/C++ solution below // DO NOT write int main() function int M = word1.size(); int N = word2.size(); if(M == 0) return N; if(N == 0) return M; vector<vector<int>> f(M+1, vector<int>(N+1, 0)); for(int i = 0; i <= M; i++){ f[i][0] = i; } for(int j = 0; j <= N; j++){ f[0][j] = j; } for(int i = 1; i <= M; i++){ for(int j = 1; j <= N; j++){ if(word1[i-1] == word2[j-1]){ f[i][j] = min(f[i-1][j]+1, f[i][j-1]+1); f[i][j] = min(f[i][j],f[i-1][j-1]); }else{ f[i][j] = min(f[i-1][j]+1, f[i][j-1]+1); f[i][j] = min(f[i][j],f[i-1][j-1]+1); } } } return f[M][N]; } };