• 2017年10月29日


    We all love recursion! Don't we?

    Consider a three-parameter recursive function w(a, b, c):

    if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns:
      1

    if a > 20 or b > 20 or c > 20, then w(a, b, c) returns:
      w(20, 20, 20)

    if a < b and b < c, then w(a, b, c) returns:
      w(a, b, c-1) + w(a, b-1, c-1) - w(a, b-1, c)

    otherwise it returns:
    w(a-1, b, c) + w(a-1, b-1, c) + w(a-1, b, c-1) - w(a-1, b-1, c-1)


    This is an easy function to implement. The problem is, if implemented directly, for moderate values of a, b and c (for example, a = 15, b = 15, c = 15), the program takes hours to run because of the massive recursion. 
     

    Input
    The input for your program will be a series of integer triples, one per line, until the end-of-file flag of -1 -1 -1. Using the above technique, you are to calculate w(a, b, c) efficiently and print the result.
     

    Output
    Print the value for w(a,b,c) for each triple.
     

    Sample Input
    1 1 1
    2 2 2
    10 4 6
    50 50 50
    -1 7 18
    -1 -1 -1
    Sample Output
    w(1, 1, 1) = 2
    w(2, 2, 2) = 4
    w(10, 4, 6) = 523
    w(50, 50, 50) = 1048576
    w(-1, 7, 18) = 1
    题目不算太难。就是共享结果。
    #include "iostream"
    #include
    #include
    using namespace std;
    int w[22][22][22];
    int rec(int a,int b,int c)
    {
    if(w[a][b][c]!=-1)
    return w[a][b][c];
        if(a<=0||b<=0||c<=0)  return 1;
    if(a==20||b==20||c==20)
    return 1048576;
    if(a
    return (rec(a,b,c-1)+rec(a,b-1,c-1)-rec(a,b-1,c));
    else
    return rec(a-1,b,c)+rec(a-1,b-1,c)+rec(a-1,b,c-1)-rec(a-1,b-1,c-1);
    }
     int main(int argc, char const *argv[])
     int a,b,c;
    memset(w,-1,sizeof(w));
    w[0][0][0]=1;
    for(int i=0;i<=21;i++)
    for (int j = 0; j <=21; ++j)
    for(int k=0;k<=21;++k)
    w[i][j][k]=rec(i,j,k);
    while(cin>>a>>b>>c)
    {
    if(a==-1&&b==-1&&c==-1)
    break;
    if(a<=0||b<=0||c<=0)
    cout<<"w"<<"("<<a<<","<<" "<<b<<","<<" "<<c<<")"<<" "<<"="<<" "<<w[0][0][0]<<endl;
        else if(a>=20||b>=20||c>=20)//要用else if
    cout<<"w"<<"("<<a<<","<<" "<<b<<","<<" "<<c<<")"<<" "<<"="<<" "<<w[20][20][20]<<endl;
        else
    cout<<"w"<<"("<<a<<","<<" "<<b<<","<<" "<<c<<")"<<" "<<"="<<" "<<w[a][b][c]<<endl;
    }
      return 0;
    }

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  • 原文地址:https://www.cnblogs.com/kuroko-ghh/p/9363377.html
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