Given a list of sorted characters letters
containing only lowercase letters, and given a target letter target
, find the smallest element in the list that is larger than the given target.
Letters also wrap around. For example, if the target is target = 'z'
and letters = ['a', 'b']
, the answer is 'a'
.
Examples:
Input: letters = ["c", "f", "j"] target = "a" Output: "c" Input: letters = ["c", "f", "j"] target = "c" Output: "f" Input: letters = ["c", "f", "j"] target = "d" Output: "f" Input: letters = ["c", "f", "j"] target = "g" Output: "j" Input: letters = ["c", "f", "j"] target = "j" Output: "c" Input: letters = ["c", "f", "j"] target = "k" Output: "c"
Note:
letters
has a length in range[2, 10000]
.letters
consists of lowercase letters, and contains at least 2 unique letters.target
is a lowercase letter.
AC code:
class Solution { public: char nextGreatestLetter(vector<char>& letters, char target) { int len = letters.size(); for (int i = 0; i < len ; ++i) { if (target < letters[i]) { return letters[i]; } } return letters[0]; } };
20ms
class Solution { public: char nextGreatestLetter(vector<char>& letters, char target) { auto it = upper_bound(letters.begin(), letters.end(), target); return it == letters.end() ? letters[0] : *it; } };
Runtime: 8 ms, faster than 97.98% of C++ online submissions for Find Smallest Letter Greater Than Target.