反转一个单链表。
示例:
输入: 1->2->3->4->5->NULL 输出: 5->4->3->2->1->NULL
进阶:
你可以迭代或递归地反转链表。你能否用两种方法解决这道题?
C#代码
/**
* Definition for singly-linked list.
* public class ListNode {
* public int val;
* public ListNode next;
* public ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode ReverseList(ListNode head) {
if (head == null)
return null;
ListNode now = new ListNode(head.val);
head = head.next;
while (head != null)
{
ListNode listNode = new ListNode(head.val);
listNode.next = now;
now = listNode;
head = head.next;
}
return now;
}
}