一、任务
用桥接模式实现在路上开车这个问题,其中,车可以是car或bus,路可以是水泥路或沥青路
二、类图
三、代码
1、Java
1 package tutorial9; 2 3 public interface AbstractRoad { 4 5 public String roadRun(); 6 }
1 package tutorial9; 2 3 public class AsphaltRoad implements AbstractRoad { 4 5 @Override 6 public String roadRun() { 7 // TODO 自动生成的方法存根 8 9 return "在沥青路上行驶"; 10 } 11 12 }
1 package tutorial9; 2 3 public class Cement implements AbstractRoad { 4 5 @Override 6 public String roadRun() { 7 // TODO 自动生成的方法存根 8 9 return "在水泥路上行驶"; 10 } 11 12 }
1 package tutorial9; 2 3 public abstract class Vehicle { 4 protected AbstractRoad road; 5 6 public Vehicle(AbstractRoad road) { 7 this.road=road; 8 } 9 10 public abstract void run(); 11 12 }
1 package tutorial9; 2 3 import java.util.Random; 4 5 public abstract class RefinedVehicle extends Vehicle { 6 7 public RefinedVehicle(AbstractRoad road) { 8 super(road); 9 // TODO 自动生成的构造函数存根 10 } 11 12 public void chooseWay(String str1) { 13 String str=str1+road.roadRun(); 14 System.out.println(str); 15 } 16 17 }
1 package tutorial9; 2 3 public class Car extends RefinedVehicle{ 4 5 public Car(AbstractRoad road) { 6 super(road); 7 // TODO 自动生成的构造函数存根 8 } 9 10 @Override 11 public void run() { 12 // TODO 自动生成的方法存根 13 System.out.println("小汽车"); 14 } 15 16 }
1 package tutorial9; 2 3 public class Bus extends RefinedVehicle { 4 5 public Bus(AbstractRoad road) { 6 super(road); 7 // TODO 自动生成的构造函数存根 8 } 9 10 @Override 11 public void run() { 12 // TODO 自动生成的方法存根 13 System.out.println("公交车"); 14 } 15 16 }
1 package tutorial9; 2 3 import java.util.Scanner; 4 5 public class Client { 6 7 public static void main(String[] args) { 8 System.out.println("*************************"); 9 System.out.println("请选择车辆:"); 10 System.out.println("1、小汽车"); 11 System.out.println("2、公交车"); 12 Scanner in=new Scanner(System.in); 13 int choice=in.nextInt(); 14 15 System.out.println("*************************"); 16 System.out.println("请选择道路:"); 17 System.out.println("1、水泥路"); 18 System.out.println("2、沥青路"); 19 int choice2=in.nextInt(); 20 21 22 if(choice==1) { 23 switch(choice2) { 24 25 case 1:{ 26 RefinedVehicle vehicle=new Car(new Cement()); 27 vehicle.chooseWay("小汽车"); 28 }break; 29 case 2:{ 30 RefinedVehicle vehicle2=new Car(new AsphaltRoad()); 31 vehicle2.chooseWay("小汽车"); 32 }break; 33 34 } 35 }else if(choice==2) { 36 switch(choice2) { 37 case 1:{ 38 RefinedVehicle vehicle=new Bus(new Cement()); 39 vehicle.chooseWay("公交车"); 40 }break; 41 case 2:{ 42 RefinedVehicle vehicle2=new Bus(new AsphaltRoad()); 43 vehicle2.chooseWay("公交车"); 44 }break; 45 46 } 47 } 48 49 50 } 51 }
2、C++
1 #include<iostream> 2 using namespace std; 3 4 //抽象路 5 class AbstractRoad { 6 7 public: 8 virtual string roadRun()=0; 9 }; 10 11 class Vehicle { 12 13 14 public: 15 16 Vehicle() { 17 18 } 19 virtual void run() {}; 20 21 }; 22 23 24 //沥青路 25 class AsphaltRoad :public AbstractRoad { 26 27 public: 28 string roadRun() { 29 30 return "在沥青路上行驶"; 31 } 32 33 }; 34 35 //水泥路 36 class Cement :public AbstractRoad { 37 38 39 public: 40 string roadRun() { 41 42 return "在水泥路上行驶"; 43 } 44 45 }; 46 47 48 class RefinedVehicle : public Vehicle { 49 50 public: 51 RefinedVehicle() { 52 53 } 54 55 56 57 58 }; 59 // 60 class Car :public RefinedVehicle { 61 private: 62 AbstractRoad *road; 63 public: 64 Car(AbstractRoad *road1) { 65 road = road1; 66 } 67 void run() { 68 // TODO 自动生成的方法存根 69 cout<<"小汽车"+road->roadRun()<<endl; 70 } 71 72 }; 73 74 class Bus :public RefinedVehicle { 75 private: 76 AbstractRoad* road; 77 78 79 public: 80 Bus(AbstractRoad* road1) { 81 road = road1; 82 } 83 void run() { 84 85 cout << "公交车" + road->roadRun() << endl; 86 } 87 88 }; 89 90 int main() { 91 92 cout<<"*************************"<<endl; 93 cout << "请选择车辆:"<<endl; 94 cout << "1、小汽车"<<endl; 95 cout << "2、公交车"<<endl; 96 int choice = 0; 97 cin >> choice; 98 cout << "*************************" << endl; 99 cout << "请选择道路:" << endl; 100 cout << "1、水泥路"<<endl; 101 cout << "2、沥青路" << endl; 102 int choice2 =0; 103 cin >> choice2; 104 105 if (choice == 1) { 106 switch (choice2) { 107 108 case 1: { 109 RefinedVehicle *vehicle = new Car(new Cement()); 110 vehicle->run(); 111 }break; 112 case 2: { 113 RefinedVehicle *vehicle2 = new Car(new AsphaltRoad()); 114 vehicle2->run(); 115 }break; 116 117 } 118 } 119 else if (choice == 2) { 120 switch (choice2) { 121 case 1: { 122 123 RefinedVehicle *vehicle = new Bus(new Cement()); 124 vehicle->run(); 125 }break; 126 case 2: { 127 RefinedVehicle *vehicle2 = new Bus(new AsphaltRoad()); 128 vehicle2->run(); 129 }break; 130 131 } 132 } 133 return 0; 134 }
四、结果截图
1、Java截图
2、C++截图