PAT 1116 Come on! Let's C [简单]

1116 Come on! Let's C （20 分）

"Let's C" is a popular and fun programming contest hosted by the College of Computer Science and Technology, Zhejiang University. Since the idea of the contest is for fun, the award rules are funny as the following:

• 0、 The Champion will receive a "Mystery Award" (such as a BIG collection of students' research papers...).
• 1、 Those who ranked as a prime number will receive the best award -- the Minions (小黄人)!
• 2、 Everyone else will receive chocolates.

Given the final ranklist and a sequence of contestant ID's, you are supposed to tell the corresponding awards.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤10​4​​), the total number of contestants. Then N lines of the ranklist follow, each in order gives a contestant's ID (a 4-digit number). After the ranklist, there is a positive integer K followed by K query ID's.

Output Specification:

For each query, print in a line ID: award where the award is Mystery Award, or Minion, or Chocolate. If the ID is not in the ranklist, print Are you kidding? instead. If the ID has been checked before, print ID: Checked.

Sample Input:

6
1111
6666
8888
1234
5555
0001
6
8888
0001
1111
2222
8888
2222

Sample Output:

8888: Minion
0001: Chocolate
1111: Mystery Award
2222: Are you kidding?
8888: Checked
2222: Are you kidding?

 题目大意：给出n个排名的id，序号代表排名，如果是第一名输出Mystery Award,素数名输出Minion，其他人输出Chocolate，重复查询提示。

水水的AC：

#include <iostream>
#include <algorithm>
#include<cstdio>
#include <map>
#include<cmath>
using namespace std;

map<int,string> award;
map<int,int> query;
bool prime(int a){
    int q=sqrt(a);
    for(int i=2;i<=q;i++){
        if(a%i==0){
            return false;
        }
    }
    return true;
}
int main()
{
    int n,no;
    scanf("%d",&n);
    for(int i=0;i<n;i++){
        scanf("%d",&no);
        if(i==0){
            award[no]="Mystery Award";
        }else{
            if(prime(i+1)){
                award[no]="Minion";
            }else{
                award[no]="Chocolate";
            }
        }
    }
    int m;
    scanf("%d",&m);
    for(int i=0;i<m;i++){
        scanf("%d",&no);
        if(award.count(no)==0){
            printf("%04d: Are you kidding?
",no);
        }else {
            if(query.count(no)==1){
                printf("%04d: Checked
",no);
            }else{//使用printf怎么输出String啊啊？好像没办法。。。
                printf("%04d: ",no);
                cout<<award[no]<<"
";
                query[no]=1;
            }
        }
    }
    return 0;
}

//有一个槽点，就是在写最后出现了个问题，代码中有注释，所以就混合使用printf和cout输出了，罪过。

1.查了一下发现是需要将其转换成char*类型，直接使用:

printf("%04d: %s
",no,award[no].c_str());

即可！c_str()就是将string转换为char*的函数！！！