• 19.1.20 [LeetCode 5]Longest Palindromic Substring


    Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000.

    Example 1:

    Input: "babad"
    Output: "bab"
    Note: "aba" is also a valid answer.
    

    Example 2:

    Input: "cbbd"
    Output: "bb"
     1 class Solution {
     2 public:
     3     string longestPalindrome(string s) {
     4         int leng = 0, size = s.length();
     5         string p;
     6         for (int i = 0; i<size; i++) {
     7             int l = 1;
     8             int S = i, E = i;
     9             while (S > 0 && E < size - 1 && s[S - 1] == s[E + 1]) {
    10                 S--, E++;
    11                 l += 2;
    12             }
    13             if (l > leng) {
    14                 p = s.substr(S, l);
    15                 leng = l;
    16             }
    17         }
    18         for (int i = 0; i < size-1; i++) {
    19             if (i + 1 > size - 1)break;
    20             int l = 0;
    21             int S = i+1, E = i;
    22             while (S > 0 && E < size - 1 && s[S - 1] == s[E + 1]) {
    23                 S--, E++;
    24                 l += 2;
    25             }
    26             if (l > leng) {
    27                 p = s.substr(S, l);
    28                 leng = l;
    29             }
    30         }
    31         return p;
    32     }
    33 };
    View Code

    从大小为1或2的回文串开始扩展

    注定失败的战争,也要拼尽全力去打赢它; 就算输,也要输得足够漂亮。
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  • 原文地址:https://www.cnblogs.com/yalphait/p/10294749.html
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