• 669. Trim a Binary Search Tree


    Given the root of a binary search tree and the lowest and highest boundaries as low and high, trim the tree so that all its elements lies in [low, high]. Trimming the tree should not change the relative structure of the elements that will remain in the tree (i.e., any node's descendant should remain a descendant). It can be proven that there is a unique answer.

    Return the root of the trimmed binary search tree. Note that the root may change depending on the given bounds.

    Example 1:

    Input: root = [1,0,2], low = 1, high = 2
    Output: [1,null,2]
    

    Example 2:

    Input: root = [3,0,4,null,2,null,null,1], low = 1, high = 3
    Output: [3,2,null,1]
    

    Example 3:

    Input: root = [1], low = 1, high = 2
    Output: [1]
    

    Example 4:

    Input: root = [1,null,2], low = 1, high = 3
    Output: [1,null,2]
    

    Example 5:

    Input: root = [1,null,2], low = 2, high = 4
    Output: [2]
    

    Constraints:

    • The number of nodes in the tree in the range [1, 104].
    • 0 <= Node.val <= 104
    • The value of each node in the tree is unique.
    • root is guaranteed to be a valid binary search tree.
    • 0 <= low <= high <= 104
    class Solution {
        public TreeNode trimBST(TreeNode root, int L, int R) {
            if (root == null) return null;
            
            if (root.val < L) return trimBST(root.right, L, R);
            if (root.val > R) return trimBST(root.left, L, R);
            
            root.left = trimBST(root.left, L, R);
            root.right = trimBST(root.right, L, R);
            
            return root;
        }
    }
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  • 原文地址:https://www.cnblogs.com/wentiliangkaihua/p/14365185.html
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