洛谷P2946 [USACO09MAR]牛飞盘队Cow Frisbee Team
动态规划
1 #include <cstdio> 2 #include <cmath> 3 #include <cstdlib> 4 #include <cstring> 5 #include <iostream> 6 #include <iomanip> 7 #include <algorithm> 8 #include <string> 9 #define LL long long 10 #define For(i,j,k) for(int i=j;i<=k;i++) 11 #define Dow(i,j,k) for(int i=j;i>=k;i--) 12 using namespace std ; 13 14 const int N = 2011,inf=1e9,Z = 1e8 ; 15 int n,mod ; 16 int f[N][1011],a[N] ; 17 18 inline LL read() 19 { 20 LL x = 0 , f = 1 ; 21 char ch = getchar() ; 22 while(ch<'0'||ch>'9') { if(ch=='-') f = -1 ; ch = getchar() ; } 23 while(ch>='0'&&ch<='9') { x = x * 10+ch-48 ; ch = getchar() ; } 24 return x * f ; 25 } 26 27 int main() 28 { 29 n = read() ; mod = read() ; 30 For(i,1,n) a[i]=read() , a[i]%=mod ; 31 For(i,0,n) 32 For(j,0,mod-1) f[i][j]=0 ; 33 f[0][0] = 1 ; 34 35 For(i,1,n) { 36 For(j,0,mod-1) { 37 f[i][j]=(f[i][j]+f[i-1][j]) % Z ; 38 f[i][j]=(f[i][j]+f[i-1][ (j-a[i]+mod) % mod ] ) % Z; 39 } 40 } 41 int ans = 0 ; 42 printf("%d ",f[n][0]-1) ; // 0 要减一 因为原来的f[0][0] = 1 43 return 0 ; 44 }