使用jsch 实现ssh tunnel

主要目的是解决比如访问敏感信息，我们通过加密隧道实现数据访问，而且对于数据进行加密

参考图

参考代码

• pom.xml

<?xml version="1.0" encoding="UTF-8"?>

<project xmlns="http://maven.apache.org/POM/4.0.0"

         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

         xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">

    <modelVersion>4.0.0</modelVersion>

 

    <groupId>com.dalong</groupId>

    <artifactId>ssh-tunnel</artifactId>

    <version>1.0-SNAPSHOT</version>

 

    <properties>

        <maven.compiler.source>8</maven.compiler.source>

        <maven.compiler.target>8</maven.compiler.target>

    </properties>

 

    <dependencies>

        <dependency>

            <groupId>com.jcraft</groupId>

            <artifactId>jsch</artifactId>

            <version>0.1.55</version>

        </dependency>

    </dependencies>

</project>

• 代码

import com.jcraft.jsch.JSch;

import com.jcraft.jsch.Session;

 

public class App {

 

    public void go() throws Exception {

        String host = "<sship>";

        String user ="<user>>";

        String password = "<password>";

        int port = 22;

        int tunnelLocalPort = 9080;

        String tunnelRemoteHost = "<containerip>";

        int tunnelRemotePort = 3306;

        JSch jsch = new JSch();

        Session session = jsch.getSession(user, host, port);

        session.setPassword(password);

        LocalUserInfo lui = new LocalUserInfo();

        session.setUserInfo(lui);

        session.connect();

        session.setPortForwardingL(tunnelLocalPort, tunnelRemoteHost, tunnelRemotePort);

        System.out.println("Connected");

    }

 

    public static void main(String[] args) throws Exception {

        App app = new App();

        app.go();

    }

} 

说明

以上代码能实现很简单，但是可以解决我们实际对于加密信息的访问，实际上好多基于容器的调试也会选择基于ssh tunnel 实现

参考资料

http://www.jcraft.com/jsch/