C语言 · 报时助手

基础练习 报时助手  

时间限制：1.0s   内存限制：512.0MB

      

 

锦囊1

　　判断，字符串输出。

锦囊2

　　按要求输出，判断特殊情况。

 

问题描述

　　给定当前的时间，请用英文的读法将它读出来。
　　时间用时h和分m表示，在英文的读法中，读一个时间的方法是：
　　如果m为0，则将时读出来，然后加上“o'clock”，如3:00读作“three o'clock”。
　　如果m不为0，则将时读出来，然后将分读出来，如5:30读作“five thirty”。
　　时和分的读法使用的是英文数字的读法，其中0~20读作：
　　0:zero, 1: one, 2:two, 3:three, 4:four, 5:five, 6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven, 12:twelve, 13:thirteen, 14:fourteen, 15:fifteen, 16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen, 20:twenty。
　　30读作thirty，40读作forty，50读作fifty。
　　对于大于20小于60的数字，首先读整十的数，然后再加上个位数。如31首先读30再加1的读法，读作“thirty one”。
　　按上面的规则21:54读作“twenty one fifty four”，9:07读作“nine seven”，0:15读作“zero fifteen”。

输入格式

　　输入包含两个非负整数h和m，表示时间的时和分。非零的数字前没有前导0。h小于24，m小于60。

输出格式

　　输出时间时刻的英文。

样例输入

0 15

样例输出

zero fifteen

 

代码一：

/*
0:zero, 1: one, 2:two, 3:three, 4:four, 5:five
6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven
12:twelve, 13:thirteen, 14:fourteen, 15:fifteen
16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen
20:twenty, 30:thirty，40:forty，50:fifty。

对于大于20小于60的数字，首先读整十的数，然后再加上个位数。
    如31首先读30再加1的读法，读作“thirty one”。
按上面的规则:
    21:54读作“twenty one fifty four”;
    9:07读作“nine seven”;
    0:15读作“zero fifteen”。
*/
#include<stdio.h>  
int main(){  
    char a[21][20]={"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen","twenty"};  
    char b[6][20]={"","","twenty","thirty","forty","fifty"};
    int h,m;
    scanf("%d%d",&h,&m);
    if(m==0){  
        if(h<=20)
            printf("%s o'clock",a[h]);
        else
            printf("%s %s",b[h/10],a[h%10]);
    }else{
        if(h<=20){
            if(m<=20){
                printf("%s %s",a[h],a[m]);
            }else{
                printf("%s %s %s",a[h],b[m/10],a[m%10]);  
            }
        }else{
            if(m<=20){  
                printf("%s %s %s",b[h/10],a[h%10],a[m]);  
            }else{
                printf("%s %s %s %s",b[h/10],a[h%10],b[m/10],a[m%10]);  
            }  
        }  
    }  
    return 0;  
}

代码二：

#include<stdio.h> 
void ass(int number){
    char n[100][100]={"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen","twenty",
    "thirty","forty","fifty"};
    int a=number/10;
    int b=number%10;
    if(number<=20){
        printf("%s",n[number]);
    }else{
        if(b!=0){
            printf(" %s",n[b]);
        }
        printf("%s",n[number+18]);
    }
}
void time_ass(int hour,int minu){
    if(minu==0){//整点 
        ass(hour);
        printf(" o'clock");
    }else{//非整点 
        ass(hour);
        printf(" ");
        ass(minu);
    }
}
int main(){
    int h,m;
    scanf("%d%d",&h,&m);
    time_ass(h,m);
    return 0;
}