c语言中指针作为参数的函数同时计算两个数的和与差

c语言中指针作为参数的函数同时计算两个数的和与差。

1、

#include <stdio.h>

void sum_dif(int n1, int n2, int *sum, int *dif)
{
    *sum = n1 + n2;
    *dif = (n1 > n2) ? (n1 - n2) : (n2 - n1);
}

int main(void)
{
    int na, nb, wa = 0, sa = 0;
    
    puts("please input two integers.");
    printf("na = "); scanf("%d", &na);
    printf("nb = "); scanf("%d", &nb);
    
    sum_dif(na, nb, &wa, &sa);
    
    printf("
wa:  %d
sa:  %d
", wa, sa);
    
    return 0; 
}