例子
$a = 336 ; $b = 33 ; function large($x,$y){ if((!isset($x))||(!isset($y))){ // echo "this function require two numbers"; return false; } if($x>$y){ return $x; }else{ return $y; } } echo large($v,$b);
假设当前数组为
array(
0=>array('key1'=>'value1' , 'key2'=>'value2'),
1=>array('key1'=>'value1' , 'key2'=>'value3'),
2=>array('key1'=>'value2' , 'key2'=>'value4'),
...
999=>array('key1'=>'value2' , 'key2'=>'value5')
)
如何将这个array中 key1的value 相同的情况下 将key2的value合并成一个新的数组。求写一个方法将原数组转化问 如下数组
array(
0=>array('value1'=>array('value2','value3')),
1=>array('value2'=>array('value4','value5')),
...
)
题主,是无论 key1是否有重复都独立吗?下面是这样的做法 $arr = array( 0=>array('key1'=>'value1' , 'key2'=>'value2'), 1=>array('key1'=>'value1' , 'key2'=>'value3'), 2=>array('key1'=>'value2' , 'key2'=>'value4'), 999=>array('key1'=>'value2' , 'key2'=>'value5') ); $result = array(); foreach ($arr as $data) { isset($result[$data['key1']]) || $result[$data['key1']] = array(); $result[$data['key1']][] = $data['key2']; } print_r($result); //输出如下 Array ( [value1] => Array ( [0] => value2 [1] => value3 ) [value2] => Array ( [0] => value4 [1] => value5 ) )