Given an array of n integers where n > 1, nums
, return an array output
such that output[i]
is equal to the product of all the elements of nums
except nums[i]
.
Solve it without division and in O(n).
For example, given [1,2,3,4]
, return [24,12,8,6]
.
Follow up:
Could you solve it with constant space complexity? (Note: The output array does not count as extra space for the purpose of space complexity analysis.)
Similar: 152. Maximum Product Subarray
42. Trapping Rain Water
1 public class Solution { 2 public int[] productExceptSelf(int[] nums) { 3 int[] output = new int[nums.length]; 4 5 output[0] = 1; 6 for (int i = 1; i < nums.length; i++) { 7 output[i] = output[i-1] * nums[i-1]; 8 } 9 10 int right = 1; 11 for (int i = nums.length-1; i>=0; i--) { 12 output[i] *= right; 13 right *= nums[i]; 14 } 15 16 return output; 17 } 18 }