• Sicily 1509. Rails


    1509. Rails

    Constraints

    Time Limit: 1 secs, Memory Limit: 32 MB

    Description

    There is a famous railway station in PopPush City. Country there is incredibly hilly. The station was built in last century. Unfortunately, funds were extremely limited that time. It was possible to establish only a surface track. Moreover, it turned out that the station could be only a dead-end one (see picture) and due to lack of available space it could have only one track.

    The local tradition is that every train arriving from the direction A continues in the direction B with coaches reorganized in some way. Assume that the train arriving from the direction A has N <= 1000 coaches numbered in increasing order 1, 2, ..., N. The chief for train reorganizations must know whether it is possible to marshal coaches continuing in the direction B so that their order will be a1, a2, ..., aN. Help him and write a program that decides whether it is possible to get the required order of coaches. You can assume that single coaches can be disconnected from the train before they enter the station and that they can move themselves until they are on the track in the direction B. You can also suppose that at any time there can be located as many coaches as necessary in the station. But once a coach has entered the station it cannot return to the track in the direction A and also once it has left the station in the direction B it cannot return back to the station.

    Input

    The input consists of blocks of lines. Each block except the last describes one train and possibly more requirements for its reorganization. In the first line of the block there is the integer N described above. In each of the next lines of the block there is a permutation of 1, 2, ..., N. The last line of the block contains just 0. 
    The last block consists of just one line containing 0.

    Output

    The output contains the lines corresponding to the lines with permutations in the input. A line of the output contains Yes if it is possible to marshal the coaches in the order required on the corresponding line of the input. Otherwise it contains No. In addition, there is one empty line after the lines corresponding to one block of the input. There is no line in the output corresponding to the last ``null'' block of the input.

    Sample Input

    5
    1 2 3 4 5
    5 4 1 2 3
    0
    6
    6 5 4 3 2 1
    0
    0

    Sample Output

    Yes
    No
    
    Yes
    

    Problem Source

    Central Europe 1997

    就说一句:注意理解输入及输出数据格式的意思。

    用栈解决。

     1 #include <iostream>
     2 #include <cstdio>
     3 #include <algorithm>
     4 #include <cstring>
     5 #include <stack> 
     6 #define rep(i,l,r) for(int i = l; i <= r; i++)
     7 #define clr(x,y) memset(x,y,sizeof(x))
     8 #define travel(x) for(Edge *p = last[x]; p; p = p -> pre)
     9 using namespace std;
    10 const int maxn = 1010;
    11 inline int read(){
    12     int ans = 0, f = 1; char c = getchar();
    13     for(; !isdigit(c); c = getchar()) if (c == '-') f = -1;
    14     for(; isdigit(c); c = getchar()) ans = ans * 10 + c - '0';
    15     return ans * f;
    16 }
    17 int n, seq[maxn];
    18 stack <int> s;
    19 void work(){
    20     while (!s.empty()) s.pop();
    21     seq[0] = read();
    22     while (seq[0]){
    23         rep(i,1,n-1) seq[i] = read();
    24         int cnt = 0;
    25         rep(i,1,n){
    26             s.push(i);
    27             while (!s.empty() && s.top() == seq[cnt]){
    28                 s.pop(); cnt++;
    29             }
    30         }
    31     if (n == cnt) printf("Yes
    "); else printf("No
    ");
    32     seq[0] = read();
    33     }
    34 }
    35 int main(){
    36     n = read();
    37     while (n){
    38         work(); printf("
    "); n = read();
    39     }
    40     return 0;
    41 }
    View Code
  • 相关阅读:
    让我用69406条评论告诉你“反贪风暴”好不好看!!!
    【大数据】爬取全部的校园新闻
    【大数据】获取一篇新闻的全部信息
    【大数据】理解爬虫原理
    中文统计
    [大数据]统计词频
    数据库表设计以及表字段命名
    设计模式的理论理解
    文件上传之oss服务器上传文件简笔
    QueryWrapper/UpdateWrapper认识
  • 原文地址:https://www.cnblogs.com/jimzeng/p/sicily1509.html
Copyright © 2020-2023  润新知