题解
Medium
BFS
一个节点只计算一次,这一点要注意。
class Solution {
public:
bool validTree(int n, vector<vector<int>>& edges) {
vector<unordered_set<int>> graph(n, unordered_set<int>());
for(auto e : edges) {
graph[e[0]].insert(e[1]);
graph[e[1]].insert(e[0]);
}
unordered_set<int> visited;
queue<int> q;
q.push(0);
while(!q.empty()) {
int t = q.front();
q.pop();
if(visited.count(t)) return false; // cycle detected
visited.insert(t);
for(auto i : graph[t]) {
q.push(i);
graph[i].erase(t); // node in one edge counts once
}
}
return visited.size() == n;
}
};