• 【HDOJ】1260 Tickets


    水DP,不过这道题目的数据好像有问题。24时制可表示范围是0~23,12时制可表示范围应为1~12。也就是说24点(即0点)其实表示为12:00:00am,而中午12:00:00其实表示为12:00:00pm,而且从12:00:00~12:59:59都是12:xx:xx pm,而13点开始则应该表示为01:xx:xx pm。题目数据比较小,虽然貌似不考虑这个也可以ac。但是,我个人是按规范做的。

     1 #include <stdio.h>
     2 
     3 #define MAXNUM 2005
     4 
     5 int times[MAXNUM];
     6 int adjacent[MAXNUM];
     7 int dp[MAXNUM];
     8 
     9 int mymin(int a, int b) {
    10     return a<b ? a:b;
    11 }
    12 
    13 void test(int *sec, int *min, int *hour) {
    14     *sec = 0;
    15     *min = 0;
    16     *hour = 1;
    17 }
    18 
    19 int main() {
    20     int case_n, n;
    21     int i, sec, min, hour;
    22     char str[3];
    23 
    24     scanf("%d", &case_n);
    25     str[2] = '';
    26     while (case_n--) {
    27         scanf("%d", &n);
    28         for (i=1; i<=n; ++i)
    29             scanf("%d", &times[i]);
    30         for (i=1; i<n; ++i)
    31             scanf("%d", &adjacent[i]);
    32         dp[0] = 0;
    33         dp[1] = times[1];
    34         for (i=2; i<=n; ++i)
    35             dp[i] = mymin(dp[i-1]+times[i], dp[i-2]+adjacent[i-1]);
    36 
    37         sec = dp[n];
    38         hour = 8;
    39         min = sec / 60; sec = sec % 60;
    40         hour += min / 60; min = min%60;
    41         //test(&sec, &min, &hour);
    42         if (hour >= 24)
    43             hour = hour%24;
    44         if (hour>=12) {
    45             if (hour > 12)
    46                 hour -= 12;
    47             printf("%02d:%02d:%02d pm
    ", hour, min, sec);
    48         } else {
    49             if (hour == 0)
    50                 hour = 12;
    51             printf("%02d:%02d:%02d am
    ", hour, min, sec);
    52         }
    53     }
    54 
    55     return 0;
    56 }
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  • 原文地址:https://www.cnblogs.com/bombe1013/p/3619822.html
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