定义一种数位simth数,该数的各位之和等于其所有质因子所有位数字之和,现给出n求大于n的最小该种数,n最大不超过8位,那么直接暴力就可以了。
/** @Date : 2017-09-08 14:12:08 * @FileName: HDU 1333 素因子 暴力.cpp * @Platform: Windows * @Author : Lweleth (SoungEarlf@gmail.com) * @Link : https://github.com/ * @Version : $Id$ */ #include <bits/stdc++.h> #define LL long long #define PII pair<int ,int> #define MP(x, y) make_pair((x),(y)) #define fi first #define se second #define PB(x) push_back((x)) #define MMG(x) memset((x), -1,sizeof(x)) #define MMF(x) memset((x),0,sizeof(x)) #define MMI(x) memset((x), INF, sizeof(x)) using namespace std; const int INF = 0x3f3f3f3f; const int N = 1e5+20; const double eps = 1e-8; LL pri[N]; LL sum[N]; bool vis[N]; int c = 0; void prime() { MMF(vis); MMF(sum); for(int i = 2; i < N; i++) { if(!vis[i]) { pri[c++] = i; LL t = i; while(t) sum[c - 1] += t % 10, t /= 10; } for(int j = 0; j < c && i * pri[j] < N; j++) { vis[i * pri[j]] = 1; if(i % pri[j] == 0) break; } } } int main() { prime(); LL n; while(cin >> n && n) { for(int i = n + 1; ;i++) { LL tmp = i; LL a = 0; while(tmp) a += tmp % 10, tmp /= 10; LL b = 0; LL t = i; for(int j = 0; j < c && pri[j] * pri[j] <= t; j++) { if(t % pri[j] == 0) { while(t % pri[j] == 0) t /= pri[j], b+=sum[j]; } } if(t != i && t > 1) while(t) b += t % 10, t/= 10; if(b == a) { printf("%lld ", i); break; } } } return 0; }