• Java基础10-集合


    作业回顾

    1. 蜜蜂和熊的生产消费关系,熊在蜂蜜满10斤吃掉。蜜蜂一次生产一斤蜂蜜,且蜜蜂生成一斤蜂蜜花费的时间是10s。
      十只蜜蜂和两只熊。

      • 蜜蜂
        bag: 20
        每次产1,耗时10ms
        满5的时候给蜜罐添加

      • 蜜罐
        max : 30


      • eat

          //蜜蜂线程
          public class Bee extends Thread{
              public static final int BAG=20;
              private int currentCount = 0;
              private String name;
              private Pool pool;
        
              public Bee(String name,Pool pool){
                  this.name = name;
                 this.pool = pool;
              }
              public void run(){
                  while(true){
                      synchronized(pool){
                          //如果蜜罐当前量已满
                          if(pool.currentNo>=Pool.MAX){
                              //如果蜜蜂自身蜜囊已满,通知熊吃蜂蜜,并进入等待队列
                              if(currentCount>=Bee.BAG){
                                  try{
                                      pool.notifyAll();
                                      pool.wait();
                                  }catch(Exception e){
                                  }
                              }
                              //如果蜜蜂自身蜜囊未满,通知熊吃蜂蜜,自身蜜囊加1
                              else{
                                  pool.notifyAll();
                                  currentCount++;
                              }
                          }
                          //如果蜜罐未满
                          else{
                              //蜜罐剩余的空间
                              int count = Pool.MAX-pool.currentNo;
                              //如果蜜蜂自身的量超过蜜罐剩余空间,则将蜜罐加满,自身的量相应减少
                              if(currentCount>=count){
                                  pool.currentNo = Pool.MAX;
                                  currentCount = currentCount -count; 
                                  pool.notifyAll();
                              }
                              //如果蜜罐自身的量不够蜜罐剩余空间,则全部加入到蜜罐中,自身的量清零
                              else{
                                  pool.currentNo += currentCount;
                                  currentCount = 0;
                              }
                          }
                      }
                  }
              }
          }
        
          //熊线程
          public class Bear extends Thread{
              private String name;
              private Pool pool;
        
              public Bear(String name, Pool pool){
                  this.name = name;
                  this.pool = pool;
              }
              public void run(){
                  while(true){
                      synchronized(pool){
                          if(pool.currentNo==Pool.MAX){
                              System.out.println(name+"吃了蜂蜜:"+ pool.currentNo);
                              pool.currentNo = 0;
                              pool.notifyAll();
                          }
                          else{
                              try{
                                  pool.wait();
                              }
                              catch(Exception e){
                              }
                          }
                      }
                  }  
              }
          }
        
          //蜜罐类
          public class Pool{
              public static final int MAX=30;
              public int currentNo = 0;
          }
        
          //测试类
          public class App{
              public static void main(String[] args){
                  Pool pool = new pool();
                  Bee bee1 = new Bee("bee-1",pool);
                  Bee bee2 = new Bee("bee-2",pool);
                  Bee bee3 = new Bee("bee-3",pool);
                  Bee bee4 = new Bee("bee-4",pool);
                  Bee bee5 = new Bee("bee-5",pool);
                  Bee bee6 = new Bee("bee-6",pool);
                  Bee bee7 = new Bee("bee-7",pool);
                  Bee bee8 = new Bee("bee-8",pool);
        
                  Bear bear1 = new Bear("bear-1",pool);
        
                  bee1.start();
                  bee2.start();
                  bee3.start();
                  bee4.start();
                  bee5.start();
                  bee6.start();
                  bee7.start();
                  bee8.start();
        
                  bear1.start();
              }
          }
        
    2. 取出两个字符串中最大的公共子串。

       public class subStringDemo {
           public static void main(String[] args) {
      
               String str1 = "how中are国you123";
               String str2 = "your国are国howu123";
      
               //System.out.println(str1.compareTo(str2));
               //String str3 = str1-str2;
      
               char c='a';
      
               //System.out.println(str1.lastIndexOf(c));
               //System.out.println(str1.substring(0,str1.length()));
      
               System.out.println(str1.charAt(0));
               System.out.println(getMaxSameStr(str1,str2));//are国
           }
       
           /**
             * Find the max same subString of two strings  
             * */  
           public static String getMaxSameStr(String str1,String str2) {
               String maxSameStr="";
               String temp="";
               int len = str1.length();
               //从大到小在str1中取子串,和str2匹配
               // 缺陷,当有两个同样长度的公共子串时,只能找到前面一个
               for(int i=0;i<len;i++) {
                   for (int j=0;j<=i;j++) {
                       temp = str1.substring(j,j+len-i);
                       if(str2.indexOf(temp)!=-1) {
                           maxSameStr=temp;
                           return maxSameStr;
                       }
                   }
               }
               return maxSameStr;
           }
       }
      
    3. StringBuffer是线程安全的,StringBuilder不是线程安全。单线程访问情况下,性能是否一致?

       public class StringBuilderBuffer {
              public static void main(String[] args) {
                     //测试单线程访问情况下,StringBuilder与 StringBuffer的性能
                     StringBuilder str1 = new StringBuilder();
                     StringBuffer str2 = new StringBuffer();
                     
                     long l1 = System.currentTimeMillis();
                     for(int i=0;i<1000000;i++) {
                            str1.append(i);
                     }
                     System.out.println(System.currentTimeMillis()-l1);//272
                     
                     long l2 = System.currentTimeMillis();
                     for(int j=0;j<1000000;j++) {
                            str2.append(j);
                     }
                     System.out.println(System.currentTimeMillis()-l2);//434, StringBuffer是线程安全的,其方法中有同步这一步骤,因此访问较慢
              }
       }
      
    4. 完成8种基本数据类包装类的练习,完成自动拆装箱操作。

       import java.io.UnsupportedEncodingException;
      
       public class StringDemo {
              public static void main(String[] args) throws Exception {
                     String str = "한국어";
                     byte[] b = str.getBytes("euc_kr");
                     /*
                     int count = 0;
                     for(int i=0;i<=0xffff;i++) {
                            count++;
                            System.out.print((char)i);
                            if(count>=20) {
                                  count = 0;
                                  System.out.println();
                            }
                     }
                     */
                     System.out.println(new String(b,"euc_kr"));//한국어
      
                     //字符串倒序输出,不支持中文
                     String str2 = "abcde123";
                     byte[] b2 = str2.getBytes("utf-8");
                     byte[] b3 = new byte[b2.length];
                     for(int i = 0;i<b2.length;i++) {
                            b3[i] = b2[b2.length-i-1];
                     }
                     System.out.println(new String(b3,"utf-8"));//321edcba
                     //自动装箱
                     Integer a = 12;
                     System.out.println(a);//12
                     //自动拆箱
                     int i = a;
                     System.out.println(i);//12
              }
       }
      
    5. substring(String str, int beginIndex, int length);
      返回一定长度的子串

       /**
        * return subString of String based on the given beginIndex and length
        * */
       public static String subString(String str, int beginIndex, int length){
           String subStr = null;
           if(str==null || str.length()==0) {
               System.out.println("字符串非法");
               return null;
           }
           if(beginIndex<0 || beginIndex>=str.length()) {
               System.out.println("开始索引非法");
               return null;
           }
      
           if(length<=0 || beginIndex+length>str.length()) {
               System.out.println("长度非法");
               return null;
           }
           return str.substring(beginIndex,beginIndex+length);
       }
      
    6. 找到自己名字对应的Unicode码

       for(int i=0;i<=0xffff;i++) {
       	if((char)i=='翟') {
       		System.out.println(i);
       		int2hex(i);
       		System.out.println((char)i);
       	}
       	if((char)i=='大') {
       		System.out.println(i);
       		int2hex(i);
       		System.out.println((char)i);
       	}
       	if((char)i=='壮') {
       		System.out.println(i);
       		int2hex(i);
       		System.out.println((char)i);
       	}
       }
      
       public static void int2hex(int l) {
           char hex[] = {'0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f'};
           System.out.print("0x");
           for(int i=28;i>=0;i=i-4) {
               System.out.print(hex[(l>>i)&0x0f]);
           }
           System.out.println();
       }
      

    StringBuffer

    1. 字符串缓冲区

    2. mutable, 可变的

    3. java.lang.AbstractStringBuilder

      |--------java.lang.StringBuffer

    4. 线程安全的

    StringBuilder

    1. 字符串构建器

    2. mutable, 可变的

    3. java.lang.AbstractStringBuilder

      |--------java.lang.StringBuilder

    4. 线程不安全

    集合类

    1. List : 列表,接口 ArrayList()

       interface java.lang.Iterable
           /|
            |------interface java.util.Collection
                      /|
                       |-----interface java.util.List
                                 |---------------class java.util.ArrayList
      
      • ArrayList读取快,写入慢

        list.add(...);

        list.get(int index);

        list.remove(int index);

        list.clear();

      • LinkedList
        存储速度快,查询速度慢
        链表,手拉手实现的对象引用

    2. []数组

      length //长度属性

    3. String

      length() //方法.

      • ==判断的是对象的内存地址,不是对象的内容
      • equals方法判断是对象的内容是否相同
    4. interface Collection

      • size() //方法

      • isEmpty() // ==null ?

      • 判断集合有效性
        col != null && col.isEmpty()

      • contains(Object obj) //判断是否包含指定的对象

      • List //有序,可重复

      • Set //无序,不重复

      • Map //key-value

    5. instanceof(非精准判断)

      运算符,判断变量是否是指定类型的对象。
      boolean b = obj instanceof String ;
      String 是final类,不可以被继承

      精准判断须用:
      this.getClass()==obj.getClass();

    练习

    1. 创建集合

      • 存放String[tom,tomas,tomsLee]

      • 存放Integer[100,200,300]

      • 存放Student{name,sex,age,标准javabean}[tom,tomas,tomsLee]

         List list = new ArrayList();
         //存放String
         list.add("tom");
         list.add("tomas");
         list.add("tomslee");
        
         //存放Integer
         list.add(100);
         list.add(new Integer(200));
         list.add(300);
        
         //存放Student
         list.add(new Student("s-1",10,'f'));
         Student s = new Student("s-2",11,'m');
         list.add(s);
         list.add(new Student("s-3",12,'m'));
        
        
         Object obj = null;
         //利用索引遍历列表
         for(int i=0;i<list.size();i++) {
             obj = list.get(i);
             if(obj instanceof String) {
                 System.out.println((String)obj);
             }
             else if(obj instanceof Integer) {
                 System.out.println(100+(Integer)obj);
             }
             else {
                 Student s2 = (Student)obj;
                 System.out.println("name:"+s2.getName()+" age:"+s2.getAge()+" sex:"+s2.getSex());
             }
         }
         System.out.println("------------------");
         //利用迭代器遍历列表
         Iterator it = list.iterator();
         while(it.hasNext()) {
             System.out.println(it.next());
         }
        
    2. Student :
      判断学生类对象内容是否相同,重写equals方法。需要三个条件同时满足name + age + sex都相同才相同。

          public boolean equals(Object obj) {
                 if(obj==null) {
                        return false;
                 }
                 if(obj==this) {
                        return true;
                 }
      
                 if(obj.getClass() == Student.class ) {
                        Student s = (Student)obj;
                        boolean nameEqu = false;
                        boolean ageEqu = false;
                        boolean sexEqu = false;
      
                        if(s.getName()==null) {
                              if(this.getName()==null) {                                  
                                     nameEqu = true;
                              }
                              else {
                                     nameEqu = false;
                              }
                        }
                        else {
                              nameEqu =  s.getName().equals(this.name);
                        }
                       /*if(this.age==s.getAge()) {
                           ageEqu = true;
                       }*/
                       ageEqu = (this.age==s.getAge());
                       /*if(this.sex == s.getSex()) {
                           sexEqu = true;
                       }*/
                       sexEqu = (this.sex == s.getSex());
                       return nameEqu && ageEqu && sexEqu;
                  }
                 return false;
          }
      
    3. 练习Vector向量类。

       //与AarryList的不同点在于,Vector是线程安全的
       Vector vector = new Vector();
       Student s1 = new Student("s1",10);
       //向集合中添加元素	
       vector.add(s1);
       vector.add(new Student("s2",20));
       
       //重复添加元素
       //添加的是重复的地址,匿名对象添加的是新地址(就算重写了equals方法,也是新地址)
       vector.add(s1);
       vector.add(new Student("s1",10));
       vector.add(new Student("s2",20));
       
       System.out.println("重复添加元素,重写equals方法");
       Iterator  it = vector.iterator();
       while(it.hasNext()) {
       	System.out.println(it.next());
       }
       
       Student2 s2 = new Student2("s3",10);
       vector.add(s2);
       vector.add(s2);
       vector.add(new Student2("s3",10));
       
       System.out.println("重复添加元素,没有重写equals方法");
       it = vector.iterator();
       while(it.hasNext()) {
       	System.out.println(it.next());
       }
       
       //在指定位置插入元素,后续元素往后串
       vector.add(0, new Student("s3",30));
       //索引越界异常
       //vector.add(10,new Student("s4",30));
       System.out.println("在指定位置插入元素");
       it = vector.iterator();
       while(it.hasNext()) {
       	System.out.println(it.next());
       }
       
       //删除元素,后续元素往前串
       System.out.println("按索引删除元素");
       vector.remove(0);
       it = vector.iterator();
       while(it.hasNext()) {
       	System.out.println(it.next());
       }
      

    作业:

    1. remove(int index); //删除指定位置的元素

    2. remove(Object o); //删除指定对象,考虑删除对象的规则是什么?

    3. removeAll(Collection col);//删除指定集合中的所有元素。

    4. contains(Object o); //是否包含

    5. contains(Collection col); //是否包含集合。

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  • 原文地址:https://www.cnblogs.com/SweetZxl/p/10345954.html
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