• HDU 1823 Luck and Love


    Luck and Love

    Time Limit: 10000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
    Total Submission(s): 4575    Accepted Submission(s): 1129


    Problem Description
    世界上上最远的距离不是相隔天涯海角
    而是我在你面前
    可你却不知道我爱你
                    ―― 张小娴

    前段日子,枫冰叶子给Wiskey做了个征婚启事,聘礼达到500万哦,天哪,可是天文数字了啊,不知多少MM蜂拥而至,顿时万人空巷,连扫地的大妈都来凑热闹来了。―_―|||
    由于人数太多,Wiskey实在忙不过来,就把统计的事情全交给了枫冰叶子,自己跑回家休息去了。这可够枫冰叶子忙的了,他要处理的有两类事情,一是得接受MM的报名,二是要帮Wiskey查找符合要求的MM中缘分最高值。
     
    Input
    本题有多个测试数据,第一个数字M,表示接下来有连续的M个操作,当M=0时处理中止。
    接下来是一个操作符C。
    当操作符为‘I’时,表示有一个MM报名,后面接着一个整数,H表示身高,两个浮点数,A表示活泼度,L表示缘分值。 (100<=H<=200, 0.0<=A,L<=100.0)
    当操作符为‘Q’时,后面接着四个浮点数,H1,H2表示身高区间,A1,A2表示活泼度区间,输出符合身高和活泼度要求的MM中的缘分最高值。 (100<=H1,H2<=200, 0.0<=A1,A2<=100.0)
    所有输入的浮点数,均只有一位小数。
     
    Output
    对于每一次询问操作,在一行里面输出缘分最高值,保留一位小数。
    对查找不到的询问,输出-1。
     
    Sample Input
    8
    I 160 50.5 60.0
    I 165 30.0 80.5
    I 166 10.0 50.0
    I 170 80.5 77.5
    Q 150 166 10.0 60.0
    Q 166 177 10.0 50.0
    I 166 40.0 99.9
    Q 166 177 10.0 50.0 0
     
    Sample Output
    80.5
    50.0
    99.9
     
    Author
    威士忌
     
    Source
     
    Recommend
    威士忌
     
    思路:第一个二维线段树,接触线段树四天了,这个题最难过,我使用树套树的方式实现二维线段树;
    就是高度为一颗线段树,然后该线段树的每一个节点都套一颗表示活跃度的线段树,二维线段树的节点
    定义为:
    struct son_Node
    {
        int ld,rd;
        double max_chance;
    };
    struct mon_Node
    {
        int leftd,rightd;
        son_Node Tree[4040];
    }TTree[450];
    在建树,更新,查询时都要对母树和子树进行操作
    这个题还应该注意的是H1 和 H2 以及 A1 和 A2
    的大小未定,在这里我RE了半个点啊
     
    代码:
    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <cmath>
    #include <algorithm>
    #include <cstdlib>
    using namespace std;
    int t_time;
    char str;
    int high;
    double active,chance;
    int left_high,right_high;
    double first_active,end_active;
    int left_active,right_active;
    double the_last_chance;
    struct son_Node
    {
        int ld,rd;
        double max_chance;
    };
    struct mon_Node
    {
        int leftd,rightd;
        son_Node Tree[4040];
    }TTree[450];
    void son_buildtree(int son_position,int mon_position,int begin,int end)
    {
        TTree[mon_position].Tree[son_position].ld = begin;
        TTree[mon_position].Tree[son_position].rd = end;
        TTree[mon_position].Tree[son_position].max_chance = 0.0;
        if(TTree[mon_position].Tree[son_position].ld == TTree[mon_position].Tree[son_position].rd)
            return ;
        son_buildtree(2 * son_position,mon_position,begin,(begin + end) / 2);
        son_buildtree(2 * son_position + 1,mon_position,(begin + end) / 2 + 1,end);
    }
    void mon_buildtree(int mon_position,int highleft,int highright,int activeleft,int activeright)
    {
        TTree[mon_position].leftd = highleft;
        TTree[mon_position].rightd = highright;
        son_buildtree(1,mon_position,activeleft,activeright);
        if(highleft == highright)
            return ;
        mon_buildtree(2 * mon_position,highleft,(highleft + highright) / 2,activeleft,activeright);
        mon_buildtree(2 * mon_position + 1,(highleft + highright) / 2 + 1,highright,activeleft,activeright);
    }
    void son_insert(int son_position,int mon_position,int position,double chance)
    {
        if(TTree[mon_position].Tree[son_position].ld <= position && TTree[mon_position].Tree[son_position].rd >= position)
        {
            if(chance - TTree[mon_position].Tree[son_position].max_chance > 0.01)
                TTree[mon_position].Tree[son_position].max_chance = chance;
        }
        if(TTree[mon_position].Tree[son_position].ld == TTree[mon_position].Tree[son_position].rd)
           return ;
        int mid = (TTree[mon_position].Tree[son_position].ld + TTree[mon_position].Tree[son_position].rd) / 2;
        if(position <= mid)
           son_insert(2 * son_position,mon_position,position,chance);
        if(position > mid)
           son_insert(2 * son_position + 1,mon_position,position,chance);
    }
    void mon_insert(int mon_position,int high_position,int active_position,double chance)
    {
        if(TTree[mon_position].leftd <= high_position && TTree[mon_position].rightd >= high_position)
        {
            son_insert(1,mon_position,active_position,chance);
        }
        if(TTree[mon_position].leftd == TTree[mon_position].rightd)
            return ;
        int mid = (TTree[mon_position].leftd + TTree[mon_position].rightd) / 2;
        if(high_position <= mid)
           mon_insert(2 * mon_position,high_position,active_position,chance);
        if(high_position > mid)
           mon_insert(2 * mon_position + 1,high_position,active_position,chance);
    }
    void son_search(int son_position,int mon_position,int begin,int end)
    {
        if(TTree[mon_position].Tree[son_position].ld == begin && TTree[mon_position].Tree[son_position].rd == end)
        {
            if(TTree[mon_position].Tree[son_position].max_chance - the_last_chance > 0.01)
                  the_last_chance = TTree[mon_position].Tree[son_position].max_chance;
            return ;
        }
        int mid = (TTree[mon_position].Tree[son_position].ld + TTree[mon_position].Tree[son_position].rd) / 2;
        if(end <= mid)
        {
             son_search(2 * son_position,mon_position,begin,end);
        }
        else if(begin > mid)
        {
             son_search(2 * son_position + 1,mon_position,begin,end);
        }
        else
        {
             son_search(2 * son_position,mon_position,begin,mid);
             son_search(2 * son_position + 1,mon_position,mid + 1,end);
             return ;
        }
    }
    void mon_search(int mon_position,int highleft,int highright,int activeleft,int activeright)
    {
        if(TTree[mon_position].leftd == highleft && TTree[mon_position].rightd == highright)
        {
             son_search(1,mon_position,activeleft,activeright);
                return ;
        }
        int mid = (TTree[mon_position].leftd + TTree[mon_position].rightd) / 2;
        if(highright <= mid)
        {
             mon_search(2 * mon_position,highleft,highright,activeleft,activeright);
        }
        else if(highleft > mid)
        {
             mon_search(2 * mon_position + 1,highleft,highright,activeleft,activeright);
        }
        else
        {
             mon_search(2 * mon_position,highleft,mid,activeleft,activeright);
             mon_search(2 * mon_position + 1,mid + 1,highright,activeleft,activeright);
            return ;
        }
    }
    int main()
    {
        while(scanf("%d",&t_time),t_time != 0)
        {
            memset(TTree,0,sizeof(TTree));
            mon_buildtree(1,1,110,1,1002);
            for(int i = 1;i <= t_time;i ++)
            {
                scanf(" %c",&str);
                if(str == 'I')
                {
                    scanf("%d%lf%lf",&high,&active,&chance);
                    high -= 90;
                    active *= 10;
                    int a = (int)active;
                    a = a + 1;
                    mon_insert(1,high,a,chance);
                }
                else
                {
                    scanf("%d%d%lf%lf",&left_high,&right_high,&first_active,&end_active);
                    left_high -= 90;
                    right_high -= 90;
                    int flag;
                    if(left_high > right_high)
                    {
                        flag = right_high;
                        right_high = left_high;
                        left_high = flag;
                    }
                    left_active = (int)10 * first_active + 1;
                    right_active = (int)10 * end_active + 1;
                    if(left_active > right_active)
                    {
                        flag = right_active;
                        right_active = left_active;
                        left_active = flag;
                    }
                    the_last_chance = 0.0;
                    mon_search(1,left_high,right_high,left_active,right_active);
                    if(the_last_chance == 0.0)
                        printf("-1
    ");
                    else
                        printf("%.1lf
    ",the_last_chance);
                }
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/GODLIKEING/p/3362092.html
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