嗯嗯嗯。。 调了一万年。
就是把树hash一下, 然后dfs两次求合法的根。
//#pragma GCC optimize(2) //#pragma GCC optimize(3) //#pragma GCC optimize(4) #include<bits/stdc++.h> #define LL long long #define LD long double #define ull unsigned long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int, int> #define SZ(x) ((int)x.size()) #define ALL(x) (x).begin(), (x).end() #define fio ios::sync_with_stdio(false); cin.tie(0); using namespace std; const int N = 1e5 + 7; const int inf = 0x3f3f3f3f; const LL INF = 0x3f3f3f3f3f3f3f3f; const int mod = 1e9 + 7; const double eps = 1e-8; const double PI = acos(-1); template<class T, class S> inline void add(T &a, S b) {a += b; if(a >= mod) a -= mod;} template<class T, class S> inline void sub(T &a, S b) {a -= b; if(a < 0) a += mod;} template<class T, class S> inline bool chkmax(T &a, S b) {return a < b ? a = b, true : false;} template<class T, class S> inline bool chkmin(T &a, S b) {return a > b ? a = b, true : false;} mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const LL B = 233333; const LL A = 2333; int n; vector<int> G[N]; LL P; LL hs[N]; LL hsson[N]; int ans; bool can[N]; bool prime(LL x) { for(int i = 2; i * i <= x; i++) { if(x % i == 0) return false; } return true; } void dfs(int u, int fa) { can[u] = true; LL pre = -1; for(auto &v : G[u]) { if(v == fa) continue; dfs(v, u); can[u] &= can[v]; if(pre == -1) pre = hs[v]; else if(~pre && hs[v] != pre) { can[u] = false; } hs[u] = hs[u] * B % P; hs[u] = (hs[u] + hs[v]) % P; } hsson[u] = pre; hs[u] = hs[u] * B % P; hs[u] = (hs[u] + A) % P; } void dfs2(int u, int fa, LL hsfa) { if(~ans) return; if(can[u]) { if(hsson[u] == -1 || hsson[u] == hsfa) { ans = u; return; } } if(u != 1) { LL val1 = hsfa, val2 = -1; int cnt1 = 0, cnt2 = 0; int pos = -1; for(auto &v : G[u]) { if(v == fa) continue; if(!can[v]) { if(pos == -1) { pos = v; } else { return; } continue; } if(val1 == -1) { val1 = hs[v]; cnt1++; } else if(hs[v] == val1) { cnt1++; } else if(val2 == -1) { val2 = hs[v]; cnt2++; } else if(hs[v] == val2) { cnt2++; } else { return; } } if(~pos) { if(cnt2) return; LL nhsfa = hsfa; for(int i = 1; i <= cnt1; i++) { nhsfa = nhsfa * B % P; nhsfa = (nhsfa + val1) % P; } nhsfa = nhsfa * B % P; nhsfa = (nhsfa + A) % P; dfs2(pos, u, nhsfa); return; } if(cnt2 >= 2) return; if(cnt2) { LL nhsfa = hsfa; for(int i = 1; i <= cnt1; i++) { nhsfa = nhsfa * B % P; nhsfa = (nhsfa + val1) % P; } nhsfa = nhsfa * B % P; nhsfa = (nhsfa + A) % P; for(auto &v : G[u]) { if(v == fa || hs[v] != val2) continue; dfs2(v, u, nhsfa); } } else { LL nhsfa = hsfa; for(int i = 1; i < cnt1; i++) { nhsfa = nhsfa * B % P; nhsfa = (nhsfa + val1) % P; } nhsfa = nhsfa * B % P; nhsfa = (nhsfa + A) % P; for(auto &v : G[u]) { if(v == fa || hs[v] != val1) continue; dfs2(v, u, nhsfa); } } } else { LL val1 = -1, val2 = -1; int cnt1 = 0, cnt2 = 0; int pos = -1; for(auto &v : G[u]) { if(v == fa) continue; if(!can[v]) { if(pos == -1) { pos = v; } else { return; } continue; } if(val1 == -1) { val1 = hs[v]; cnt1++; } else if(hs[v] == val1) { cnt1++; } else if(val2 == -1) { val2 = hs[v]; cnt2++; } else if(hs[v] == val2) { cnt2++; } else { return; } } if(~pos) { if(cnt2) return; LL nhsfa = hsfa; for(int i = 1; i <= cnt1; i++) { nhsfa = nhsfa * B % P; nhsfa = (nhsfa + val1) % P; } nhsfa = nhsfa * B % P; nhsfa = (nhsfa + A) % P; dfs2(pos, u, nhsfa); return; } if(cnt1 && !cnt2) { LL nhsfa = hsfa; for(int i = 1; i < cnt1; i++) { nhsfa = nhsfa * B % P; nhsfa = (nhsfa + val1) % P; } nhsfa = nhsfa * B % P; nhsfa = (nhsfa + A) % P; for(auto &v : G[u]) { if(v == fa || hs[v] != val1) continue; dfs2(v, u, nhsfa); } } else { if(cnt1 > cnt2) { swap(cnt1, cnt2); swap(val1, val2); } if(cnt1 > 1) return; if(cnt2 > 1) { LL nhsfa = hsfa; for(int i = 1; i <= cnt2; i++) { nhsfa = nhsfa * B % P; nhsfa = (nhsfa + val2) % P; } nhsfa = nhsfa * B % P; nhsfa = (nhsfa + A) % P; for(auto &v : G[u]) { if(v == fa || hs[v] != val1) continue; dfs2(v, u, nhsfa); } } else { LL nhsfa1 = hsfa, nhsfa2 = hsfa; nhsfa1 = (nhsfa1 * B + val2) % P; nhsfa1 = (nhsfa1 * B + A) % P; nhsfa2 = (nhsfa2 * B + val1) % P; nhsfa2 = (nhsfa2 * B + A) % P; for(auto &v : G[u]) { if(v == fa) continue; if(hs[v] == val1) { dfs2(v, u, nhsfa1); } else if(hs[v] == val2) { dfs2(v, u, nhsfa2); } } } } } } int main() { while(P <= 500000000) P = rng() % 900000000; while(!prime(P)) P++; scanf("%d", &n); for(int i = 1; i < n; i++) { int u, v; scanf("%d%d", &u, &v); G[u].push_back(v); G[v].push_back(u); } int Rt = 1; dfs(Rt, 0); if(can[Rt]) { printf("%d ", Rt); return 0; } ans = -1; dfs2(Rt, 0, 0); printf("%d ", ans); return 0; } /* */