http://acm.hdu.edu.cn/showproblem.php?pid=2053
Problem Description
There are many lamps in a line. All of them are off at first. A series of operations are carried out on these lamps. On the i-th operation, the lamps whose numbers are the multiple of i change the condition ( on to off and off to on ).
Input
Each test case contains only a number n ( 0< n<= 10^5) in a line.
Output
Output the condition of the n-th lamp after infinity operations ( 0 - off, 1 - on ).
Sample Input
1
5
Sample Output
1
0
代码:
#include <bits/stdc++.h> using namespace std; const int maxn=1e5+10; int a[maxn]; int A(int n) { if(n==0) return 1; return 0; } int B(int i) { for(int j=i;j<=maxn;j+=i) { a[j]=A(a[j]); } } int main() { for(int i=1;i<=1e5;i++) { B(i); } int n; while(~scanf("%d",&n)) { printf("%d ",a[n]); } return 0; }