FileUpload控件默认不支持服务端的ONCHANGE事件,此时用一种变通的方法借用客户端的onchange事件,调用__doPostBack方法来用LinkButton的OnClick事件模拟一个事件触发的过程,具体代码如下:
客户端:
- <asp:FileUpload ID="fuPhoto" onchange="javascript:__doPostBack('lbUploadPhoto','')"
- runat="server" ToolTip="选择图片" />
- <asp:LinkButton ID="lbUploadPhoto" runat="server" OnClick="lbUploadPhoto_Click"></asp:LinkButton>
后台代码:
- //自动上传事件
- protected void lbUploadPhoto_Click(object sender, EventArgs e)
- {
- fileUpload();
- }
- //从控件上传文件
- public void fileUpload()
- {
- if (fuPhoto.PostedFile != null && fuPhoto.PostedFile.ContentLength > 0)
- {
- string ext = System.IO.Path.GetExtension(fuPhoto.PostedFile.FileName).ToLower();
- if (ext != ".jpg" && ext != ".jepg" && ext != ".bmp" && ext != ".gif")
- {
- return;
- }
- string filename = "Image_" + DateTime.Now.ToString("yyyyMMddHHmmss") + ext;
- string path = "./UploadPhoto/" + filename;
- fuPhoto.PostedFile.SaveAs(Server.MapPath(path));
- Response.Redirect("ImageCut.aspx?Picurl=" + Server.UrlEncode(path));
- }
- else
- {
- //do some thing;
- }
- }