• Cheap Kangaroo


    There are N kangaroos going out to eat at an Indian restaurant. The ith kangaroo wants to eat exactly xi food. The kangaroos all want to order the same size of plates, but each one can order more than one plate for themselves if they need to. If the kangaroo orders more than he needs, he can simply hide the leftovers in his pouch.

    At this Indian restaurant, the cost of the plate is the same as its size. Since Karl the Kangaroo is paying and is low on money, he wants to know what is the minimum cost to feed all N kangaroos and what is the largest possible size of the plates that satisfies this minimum cost?

    Input

    The first line of input is T – the number of test cases.

    The first line of each test case is an integer N (1 ≤ N ≤ 105).

    The second line contains N space-separated integers xi (1 ≤ xi ≤ 109).

    Output

    For each test case, output a line containing two space-separated integers – the minimum cost and the maximum plate size that corresponds to when the total cost is minimized.

    Example

    input

    Copy

    2
    1
    5
    2
    4 2
    

    output

    Copy

    5 5
    6 2

    题意:先是和,后是最大公约数

    #include<algorithm>
    #include<stdlib.h>
    #include<stdio.h>
    #include<string.h>
    using namespace std;
    int main()
    {
        int t;
        scanf("%d",&t);
        while(t--)
        {
            long long int n,i,k,a[100100],sum=0;
            scanf("%lld",&n);
            for(i=0;i<n;i++)
               scanf("%lld",&a[i]);
            k=a[0];
            for(i=1;i<n;i++)
            {
                k=__gcd(k,a[i]);
            }
            for(i=0;i<n;i++ )
              sum+=a[i];
            printf("%lld %lld
    ",sum,k);
        }
        return 0;
    }
  • 相关阅读:
    Java多线程系列目录(共43篇)
    Java 集合系列目录(Category)
    Floyd算法(三)之 Java详解
    Floyd算法(二)之 C++详解
    Floyd算法(一)之 C语言详解
    Dijkstra算法(三)之 Java详解
    Dijkstra算法(二)之 C++详解
    Dijkstra算法(一)之 C语言详解
    Prim算法(三)之 Java详解
    Prim算法(二)之 C++详解
  • 原文地址:https://www.cnblogs.com/zcy19990813/p/9702813.html
Copyright © 2020-2023  润新知