题目链接:https://vjudge.net/problem/UVA-1589
题目翻译摘自《算法禁赛入门经典》
题目大意
考虑一个象棋残局,其中红方有 n(2 ≤ n ≤ 7)个棋子,黑方只有一个将。红方除了有一个 帅(G)之外还有3种可能的棋子:车(R),马(H),炮(C),并且需要考虑“蹩马 腿”与将和帅不能照面(将、帅如果同在一条直线上,中间又不隔着任何棋 子的情况下,走子的一方获胜)的规则。
输入所有棋子的位置,保证局面合法并且红方已经将军。你的任务是判断红方是否已经 把黑方将死。
分析
略。
代码如下
1 #include <bits/stdc++.h> 2 using namespace std; 3 4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0); 5 #define Rep(i,n) for (int i = 0; i < (n); ++i) 6 #define For(i,s,t) for (int i = (s); i <= (t); ++i) 7 #define rFor(i,t,s) for (int i = (t); i >= (s); --i) 8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i) 9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i) 10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i) 11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i) 12 13 #define pr(x) cout << #x << " = " << x << " " 14 #define prln(x) cout << #x << " = " << x << endl 15 16 #define LOWBIT(x) ((x)&(-x)) 17 18 #define ALL(x) x.begin(),x.end() 19 #define INS(x) inserter(x,x.begin()) 20 21 #define ms0(a) memset(a,0,sizeof(a)) 22 #define msI(a) memset(a,inf,sizeof(a)) 23 #define msM(a) memset(a,-1,sizeof(a)) 24 25 #define MP make_pair 26 #define PB push_back 27 #define ft first 28 #define sd second 29 30 template<typename T1, typename T2> 31 istream &operator>>(istream &in, pair<T1, T2> &p) { 32 in >> p.first >> p.second; 33 return in; 34 } 35 36 template<typename T> 37 istream &operator>>(istream &in, vector<T> &v) { 38 for (auto &x: v) 39 in >> x; 40 return in; 41 } 42 43 template<typename T1, typename T2> 44 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) { 45 out << "[" << p.first << ", " << p.second << "]" << " "; 46 return out; 47 } 48 49 inline int gc(){ 50 static const int BUF = 1e7; 51 static char buf[BUF], *bg = buf + BUF, *ed = bg; 52 53 if(bg == ed) fread(bg = buf, 1, BUF, stdin); 54 return *bg++; 55 } 56 57 inline int ri(){ 58 int x = 0, f = 1, c = gc(); 59 for(; c<48||c>57; f = c=='-'?-1:f, c=gc()); 60 for(; c>47&&c<58; x = x*10 + c - 48, c=gc()); 61 return x*f; 62 } 63 64 template<class T> 65 inline string toString(T x) { 66 ostringstream sout; 67 sout << x; 68 return sout.str(); 69 } 70 71 typedef long long LL; 72 typedef unsigned long long uLL; 73 typedef pair< double, double > PDD; 74 typedef pair< int, int > PII; 75 typedef pair< int, PII > PIPII; 76 typedef pair< string, int > PSI; 77 typedef pair< int, PSI > PIPSI; 78 typedef set< int > SI; 79 typedef set< PII > SPII; 80 typedef vector< int > VI; 81 typedef vector< VI > VVI; 82 typedef vector< PII > VPII; 83 typedef map< int, int > MII; 84 typedef map< int, string > MIS; 85 typedef map< int, PII > MIPII; 86 typedef map< PII, int > MPIII; 87 typedef map< string, int > MSI; 88 typedef map< string, string > MSS; 89 typedef map< PII, string > MPIIS; 90 typedef map< PII, PII > MPIIPII; 91 typedef multimap< int, int > MMII; 92 typedef multimap< string, int > MMSI; 93 //typedef unordered_map< int, int > uMII; 94 typedef pair< LL, LL > PLL; 95 typedef vector< LL > VL; 96 typedef vector< VL > VVL; 97 typedef priority_queue< int > PQIMax; 98 typedef priority_queue< int, VI, greater< int > > PQIMin; 99 const double EPS = 1e-6; 100 const LL inf = 0x7fffffff; 101 const LL infLL = 0x7fffffffffffffffLL; 102 const LL mod = 1e9 + 7; 103 const int maxN = 1e4 + 7; 104 const LL ONE = 1; 105 const LL evenBits = 0xaaaaaaaaaaaaaaaa; 106 const LL oddBits = 0x5555555555555555; 107 108 struct Point{ 109 int X, Y; 110 111 Point() {} 112 Point(int x, int y) : X(x), Y(y) {} 113 114 bool between(const Point &x, const Point &y) { 115 if(x.X == y.X && X == x.X && Y > min(x.Y, y.Y) && Y < max(x.Y, y.Y)) return true; 116 if(x.Y == y.Y && Y == x.Y && X > min(x.X, y.X) && X < max(x.X, y.X)) return true; 117 return false; 118 } 119 120 Point operator+ (const Point &x) const { 121 return Point(X + x.X, Y + x.Y); 122 } 123 124 bool operator== (const Point &x) const { 125 return X == x.X && Y == x.Y; 126 } 127 128 bool operator!= (const Point &x) const { 129 return !(*this == x); 130 } 131 }; 132 133 istream &operator>> (istream &in, Point &x) { 134 in >> x.X >> x.Y; 135 return in; 136 } 137 138 ostream &operator<< (ostream &out, const Point &x) { 139 out << "(" << x.X << ", " << x.Y << ")" << endl; 140 return out; 141 } 142 143 int N; 144 Point BGpos, RGpos; 145 multimap< string, Point > R; 146 Point d[] = {Point(-1, 0), Point(0, 1), Point(1, 0), Point(0, -1)}; 147 Point h[] = {Point(-2, -1), Point(-2, 1), Point(-1, 2), Point(1, 2), Point(2, 1), Point(2, -1), Point(1, -2), Point(-1, -2)}; 148 bool ans; 149 150 bool checkR(Point x, Point y) { 151 if(x.X != y.X && x.Y != y.Y) return false; 152 foreach(i, R) if(i->sd != x && i->sd != y && i->sd.between(x, y)) return false; 153 return true; 154 } 155 156 bool checkG(Point x, Point y) { 157 return checkR(x, y); 158 } 159 160 bool checkH(Point x, Point y) { 161 int vis[4] = {0}; 162 Rep(i, 4) foreach(j, R) if(x + d[i] == j->sd) vis[i] = 1; 163 Rep(i, 8) if(!vis[i >> 1] && x + h[i] == y) return true; 164 return false; 165 } 166 167 bool checkC(Point x, Point y) { 168 int cnt = 0; 169 foreach(i, R) if(i->sd != x && i->sd != y && i->sd.between(x, y)) ++cnt; 170 return cnt == 1; 171 } 172 173 MSI f_id = {MP("G", 0), MP("R", 1), MP("H", 2), MP("C", 3)}; 174 bool (*func[4])(Point, Point) = {checkG, checkR, checkH, checkC}; 175 176 bool ischeck(Point x) { 177 if(!(x.Y < 7 && x.Y > 3 && x.X > 0 && x.X < 4)) return true; 178 // 枚举每个棋子能不能将死对面 179 foreach(i, R) if(i->sd != x && func[f_id[i->ft]](i->sd, x)) return true; 180 return false; 181 } 182 183 int main(){ 184 //freopen("MyOutput.txt","w",stdout); 185 //freopen("input.txt","r",stdin); 186 INIT(); 187 while(cin >> N >> BGpos) { 188 if(!N) break; 189 ans = true; 190 R.clear(); 191 Rep(i, N) { 192 string tmp; 193 Point t; 194 cin >> tmp >> t; 195 R.insert(MP(tmp, t)); 196 if(tmp == "G") RGpos = t; 197 } 198 199 if(checkG(RGpos, BGpos)) { // 将帅照面 200 cout << "NO" << endl; 201 continue; 202 } 203 Rep(i, 4) { 204 if(!ischeck(BGpos + d[i])) { 205 ans = false; 206 break; 207 } 208 } 209 if(ans) cout << "YES" << endl; 210 else cout << "NO" << endl; 211 } 212 return 0; 213 }