• UVA 1589 Xiangqi


    题目链接:https://vjudge.net/problem/UVA-1589

    题目翻译摘自《算法禁赛入门经典》

    题目大意

      考虑一个象棋残局,其中红方有 n(2 ≤ n ≤ 7)个棋子,黑方只有一个将。红方除了有一个 帅(G)之外还有3种可能的棋子:车(R),马(H),炮(C),并且需要考虑“蹩马 腿”与将和帅不能照面(将、帅如果同在一条直线上,中间又不隔着任何棋 子的情况下,走子的一方获胜)的规则。

      输入所有棋子的位置,保证局面合法并且红方已经将军。你的任务是判断红方是否已经 把黑方将死。

    分析

      略。

    代码如下

      1 #include <bits/stdc++.h>
      2 using namespace std;
      3  
      4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
      5 #define Rep(i,n) for (int i = 0; i < (n); ++i)
      6 #define For(i,s,t) for (int i = (s); i <= (t); ++i)
      7 #define rFor(i,t,s) for (int i = (t); i >= (s); --i)
      8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i)
      9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i)
     10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i)
     11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i)
     12  
     13 #define pr(x) cout << #x << " = " << x << "  "
     14 #define prln(x) cout << #x << " = " << x << endl
     15  
     16 #define LOWBIT(x) ((x)&(-x))
     17  
     18 #define ALL(x) x.begin(),x.end()
     19 #define INS(x) inserter(x,x.begin())
     20  
     21 #define ms0(a) memset(a,0,sizeof(a))
     22 #define msI(a) memset(a,inf,sizeof(a))
     23 #define msM(a) memset(a,-1,sizeof(a))
     24 
     25 #define MP make_pair
     26 #define PB push_back
     27 #define ft first
     28 #define sd second
     29  
     30 template<typename T1, typename T2>
     31 istream &operator>>(istream &in, pair<T1, T2> &p) {
     32     in >> p.first >> p.second;
     33     return in;
     34 }
     35  
     36 template<typename T>
     37 istream &operator>>(istream &in, vector<T> &v) {
     38     for (auto &x: v)
     39         in >> x;
     40     return in;
     41 }
     42  
     43 template<typename T1, typename T2>
     44 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) {
     45     out << "[" << p.first << ", " << p.second << "]" << "
    ";
     46     return out;
     47 }
     48 
     49 inline int gc(){
     50     static const int BUF = 1e7;
     51     static char buf[BUF], *bg = buf + BUF, *ed = bg;
     52     
     53     if(bg == ed) fread(bg = buf, 1, BUF, stdin);
     54     return *bg++;
     55 } 
     56 
     57 inline int ri(){
     58     int x = 0, f = 1, c = gc();
     59     for(; c<48||c>57; f = c=='-'?-1:f, c=gc());
     60     for(; c>47&&c<58; x = x*10 + c - 48, c=gc());
     61     return x*f;
     62 }
     63 
     64 template<class T>
     65 inline string toString(T x) {
     66     ostringstream sout;
     67     sout << x;
     68     return sout.str();
     69 }
     70  
     71 typedef long long LL;
     72 typedef unsigned long long uLL;
     73 typedef pair< double, double > PDD;
     74 typedef pair< int, int > PII;
     75 typedef pair< int, PII > PIPII;
     76 typedef pair< string, int > PSI;
     77 typedef pair< int, PSI > PIPSI;
     78 typedef set< int > SI;
     79 typedef set< PII > SPII;
     80 typedef vector< int > VI;
     81 typedef vector< VI > VVI;
     82 typedef vector< PII > VPII;
     83 typedef map< int, int > MII;
     84 typedef map< int, string > MIS;
     85 typedef map< int, PII > MIPII;
     86 typedef map< PII, int > MPIII;
     87 typedef map< string, int > MSI;
     88 typedef map< string, string > MSS;
     89 typedef map< PII, string > MPIIS;
     90 typedef map< PII, PII > MPIIPII;
     91 typedef multimap< int, int > MMII;
     92 typedef multimap< string, int > MMSI;
     93 //typedef unordered_map< int, int > uMII;
     94 typedef pair< LL, LL > PLL;
     95 typedef vector< LL > VL;
     96 typedef vector< VL > VVL;
     97 typedef priority_queue< int > PQIMax;
     98 typedef priority_queue< int, VI, greater< int > > PQIMin;
     99 const double EPS = 1e-6;
    100 const LL inf = 0x7fffffff;
    101 const LL infLL = 0x7fffffffffffffffLL;
    102 const LL mod = 1e9 + 7;
    103 const int maxN = 1e4 + 7;
    104 const LL ONE = 1;
    105 const LL evenBits = 0xaaaaaaaaaaaaaaaa;
    106 const LL oddBits = 0x5555555555555555;
    107 
    108 struct Point{
    109     int X, Y;
    110     
    111     Point() {}
    112     Point(int x, int y) : X(x), Y(y) {}
    113     
    114     bool between(const Point &x, const Point &y) {
    115         if(x.X == y.X && X == x.X && Y > min(x.Y, y.Y) && Y < max(x.Y, y.Y)) return true;
    116         if(x.Y == y.Y && Y == x.Y && X > min(x.X, y.X) && X < max(x.X, y.X)) return true;
    117         return false;
    118     }
    119     
    120     Point operator+ (const Point &x) const {
    121         return Point(X + x.X, Y + x.Y);
    122     }
    123     
    124     bool operator== (const Point &x) const {
    125         return X == x.X && Y == x.Y;
    126     }
    127     
    128     bool operator!= (const Point &x) const {
    129         return !(*this == x);
    130     }
    131 };
    132 
    133 istream &operator>> (istream &in, Point &x) {
    134     in >> x.X >> x.Y;
    135     return in;
    136 }
    137 
    138 ostream &operator<< (ostream &out, const Point &x) {
    139     out << "(" << x.X << ", " << x.Y << ")" << endl;
    140     return out;
    141 }
    142 
    143 int N;
    144 Point BGpos, RGpos; 
    145 multimap< string, Point > R;
    146 Point d[] = {Point(-1, 0), Point(0, 1), Point(1, 0), Point(0, -1)};
    147 Point h[] = {Point(-2, -1), Point(-2, 1), Point(-1, 2), Point(1, 2), Point(2, 1), Point(2, -1), Point(1, -2), Point(-1, -2)};
    148 bool ans;
    149 
    150 bool checkR(Point x, Point y) {
    151     if(x.X != y.X && x.Y != y.Y) return false;
    152     foreach(i, R) if(i->sd != x && i->sd != y && i->sd.between(x, y)) return false;
    153     return true;
    154 }
    155 
    156 bool checkG(Point x, Point y) {
    157     return checkR(x, y);
    158 }
    159 
    160 bool checkH(Point x, Point y) {
    161     int vis[4] = {0};
    162     Rep(i, 4) foreach(j, R) if(x + d[i] == j->sd) vis[i] = 1;
    163     Rep(i, 8) if(!vis[i >> 1] && x + h[i] == y) return true;
    164     return false;
    165 }
    166 
    167 bool checkC(Point x, Point y) {
    168     int cnt = 0;
    169     foreach(i, R) if(i->sd != x && i->sd != y && i->sd.between(x, y)) ++cnt;
    170     return cnt == 1;
    171 }
    172 
    173 MSI f_id = {MP("G", 0), MP("R", 1), MP("H", 2), MP("C", 3)};
    174 bool (*func[4])(Point, Point) = {checkG, checkR, checkH, checkC};
    175 
    176 bool ischeck(Point x) {
    177     if(!(x.Y < 7 && x.Y > 3 && x.X > 0 && x.X < 4)) return true;
    178     // 枚举每个棋子能不能将死对面 
    179     foreach(i, R) if(i->sd != x && func[f_id[i->ft]](i->sd, x)) return true;
    180     return false;
    181 }
    182 
    183 int main(){
    184     //freopen("MyOutput.txt","w",stdout);
    185     //freopen("input.txt","r",stdin);
    186     INIT();
    187     while(cin >> N >> BGpos) {
    188         if(!N) break;
    189         ans = true;
    190         R.clear();
    191         Rep(i, N) {
    192             string tmp;
    193             Point t;
    194             cin >> tmp >> t;
    195             R.insert(MP(tmp, t));
    196             if(tmp == "G") RGpos = t;
    197         }
    198         
    199         if(checkG(RGpos, BGpos)) { // 将帅照面 
    200             cout << "NO" << endl;
    201             continue;
    202         }
    203         Rep(i, 4) {
    204             if(!ischeck(BGpos + d[i])) {
    205                 ans = false;
    206                 break;
    207             }
    208         }
    209         if(ans) cout << "YES" << endl;
    210         else cout << "NO" << endl;
    211     }
    212     return 0;
    213 }
    View Code
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  • 原文地址:https://www.cnblogs.com/zaq19970105/p/11031466.html
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