• 920. 会议室


    920. 会议室

    中文English

    给定一系列的会议时间间隔,包括起始和结束时间[[s1,e1],[s2,e2],…(si < ei),确定一个人是否可以参加所有会议。

    样例

    样例1

    输入: intervals = [(0,30),(5,10),(15,20)]
    输出: false
    解释:
    (0,30), (5,10) 和 (0,30),(15,20) 这两对会议会冲突
    

    样例2

    输入: intervals = [(5,8),(9,15)]
    输出: true
    解释:
    这两个时间段不会冲突
    

    注意事项

    (0,8),(8,10)在8这这一时刻不冲突

    """
    Definition of Interval.
    class Interval(object):
        def __init__(self, start, end):
            self.start = start
            self.end = end
    """
    
    class Solution:
        """
        @param intervals: an array of meeting time intervals
        @return: if a person could attend all meetings
        """
     
        def canAttendMeetings(self, intervals):
            # Write your code here
            if intervals == []:
                return True
            
            intervals = sorted(intervals,key = lambda  num: num.start)
                
            start = intervals[0].start
            end = intervals[0].end
            for i in range(1,len(intervals)):
                if intervals[i].start < end:
                    return False
                start = intervals[i].start
                end = intervals[i].end
            return True
        大致思路:
        1.判断时间之间是否重合,如果重合的话,直接返回False,否则true
     
    最简写法:
    """
    Definition of Interval.
    class Interval(object):
        def __init__(self, start, end):
            self.start = start
            self.end = end
    """
    
    class Solution:
        """
        @param intervals: an array of meeting time intervals
        @return: if a person could attend all meetings
        """
        def canAttendMeetings(self, intervals):
            end = 0
            for interval in sorted(intervals,key = lambda num:num.start):
                if interval.start < end:
                    return False
                end = interval.end
            return True
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  • 原文地址:https://www.cnblogs.com/yunxintryyoubest/p/12571878.html
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