• [HAOI2011]Problem b


    description

    [sum_{i=1}^{n} sum_{j=1}^{m}[gcd(i, j)==k] ]

    solution

    [egin{align} sum_{i=1}^{n}sum_{j=1}^{m}[gcd(i, j)==k] &= sum_{i=1}^{lfloorfrac{n}{k} floor}sum_{j=1}^{lfloorfrac{m}{k} floor}[gcd(i, j)==1]\ &=sum_{i=1}^{lfloorfrac{n}{k} floor}sum_{j=1}^{lfloorfrac{m}{k} floor}sum_{d|gcd(i, j)}mu(d)\ &=sum_{d=1}sum_{i=1}^{lfloorfrac{n}{k} floor}[d|i]sum_{j=1}^{lfloorfrac{m}{k} floor}[d|j]\ &=sum_{d=1}lfloorfrac{n}{kd} floorlfloorfrac{m}{kd} floor end{align} ]

    [sum_{i=a}^{n}sum_{j=b}^{m}[gcd(i, j)==k]=sum_{i=1}^{n}sum_{j=1}^{m}[gcd(i, j)==k]-sum_{i=1}^{a-1}sum_{j=1}^{m}[gcd(i, j)==k]-sum_{i=1}^{n}sum_{j=1}^{b-1}[gcd(i, j)==k]+sum_{i=1}^{a-1}sum_{j=1}^{b-1}[gcd(i, j)==k] ]

    code
    #include<iostream>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<cmath>
    #include<algorithm>
    #include<vector>
    #include<map>
    #include<bitset>
    #include<queue>
    #include<set>
    #define R register
    #define mod 998244353
    #define debug puts("wn")
    #define next MabLcdG
    #define pos(i, j) (i*m+j)
    using namespace std;
    typedef long long ll; 
    typedef long double ld;
    typedef double dl;
    typedef unsigned long long ull;
    template<typename T>void read(T &x);
    template<typename T>void write(T x);
    template<typename T>void writesp(T x);
    template<typename T>void writeln(T x);
    
    const ll N=5e4+5, lim=5e4;
    
    ll mu[N], prime[N], tot;
    bool flag[N];
    inline void calc_mu(){
    	flag[1]=true; mu[1]=1;
    	for(R ll i=2; i<=lim; i++){
    		if(!flag[i]){
    			prime[++tot]=i;
    			mu[i]=-1;
    		}
    		for(R ll j=1; j<=tot && i*prime[j]<=lim; j++){
    			flag[i*prime[j]]=true;
    			if(i%prime[j]==0){
    				mu[i*prime[j]]=0;
    				break;
    			}
    			mu[i*prime[j]]=-mu[i];
    		}
    	}
    	for(R ll i=1; i<=lim; i++) mu[i]+=mu[i-1];
    }
    
    ll T;
    
    inline ll solve(ll n, ll m){
    	ll res=0;
    	for(R ll l=1, r; l<=n && l<=m; l=r+1){
    		r=min(n/(n/l), m/(m/l));
    		res+=(mu[r]-mu[l-1])*(n/l)*(m/l);
    	} 
    	return res;
    }
    int main(){
    	calc_mu();
    	read(T);
    	ll a, b, c, d, k;
    	while(T--){
    		read(a); read(b); read(c); read(d); read(k);
    		writeln(solve(b/k, d/k)-solve((a-1)/k, d/k)-solve(b/k, (c-1)/k)+solve((a-1)/k, (c-1)/k));
    	}
    }
    
    template<typename T>void read(T &x){
    	char wn=getchar(); ll t=1; x=0;
    	while(wn<'0' || wn>'9'){
    		if(wn=='-') t=-1;
    		wn=getchar();
    	}
    	while(wn>='0' && wn<='9'){
    		x=x*10+wn-'0'; wn=getchar();
    	}
    	x*=t;
    }
    
    template<typename T>void write(T x){
    	if(x<0){putchar('-'); x=-x;}
    	if(x<=9){putchar(x+'0'); return;}
    	write(x/10); putchar(x%10+'0');
    }
    
    template<typename T>void writeln(T x){
    	write(x); putchar('
    ');
    }
    
    template<typename T>void writesp(T x){
    	write(x); putchar(' ');
    }
    
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  • 原文地址:https://www.cnblogs.com/ylwtsq/p/13840468.html
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