[leetcode.com]算法题目

Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).

For example, this binary tree is symmetric:

    1
   / 
  2   2
 /  / 
3  4 4  3

But the following is not:

    1
   / 
  2   2
      
   3    3

Note:
Bonus points if you could solve it both recursively and iteratively.

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isSymmetric(TreeNode *root) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        if (!root) return true;
        
        if(!root->left && !root->right)
            return true;
            
        if(!root->left && root->right)
            return false;
        
        if(root->left && !root->right)
            return false;
            
        if(root->left->val == root->right->val)
            return symmetricTree(root->left, root->right);
        else
            return false;
    }
    
    bool symmetricTree(TreeNode *a, TreeNode *b){
        if(!a && !b)
            return true;
            
        if((!a && b) || (a && !b))
            return false;
            
        if(a->val == b->val)
            return symmetricTree(a->left, b->right) && symmetricTree(a->right, b->left);
        else
            return false;
    }
};

思路：和判断两个tree是否相同有点类似，但是要注意这里判断的是是否对称。好久不写代码，看了别人写的这道题答案，感觉自己写的代码很不标准。不管怎样，先贴出来，慢慢进步吧。