[LintCode] 480. Binary Tree Paths

Given a binary tree, return all root-to-leaf paths.

Solution 1:

 1 /**
 2  * Definition of TreeNode:
 3  * public class TreeNode {
 4  *     public int val;
 5  *     public TreeNode left, right;
 6  *     public TreeNode(int val) {
 7  *         this.val = val;
 8  *         this.left = this.right = null;
 9  *     }
10  * }
11  */
12 
13 public class Solution {
14     /**
15      * @param root: the root of the binary tree
16      * @return: all root-to-leaf paths
17      */
18     public List<String> binaryTreePaths(TreeNode root) {
19         // write your code here
20         List<String> list = new ArrayList<>();
21         StringBuilder sb = new StringBuilder();
22         traversal(list, root, sb);
23         return list;
24     }
25 
26     private void traversal(List<String> list, TreeNode root, StringBuilder sb) {
27         if (root == null) {
28             return;
29         }
30         if (root.left == null && root.right == null) {
31             sb.append(root.val);
32             list.add(new String(sb));
33             return;
34         }
35         int len = sb.length();
36         if (root.left != null) {
37             sb.append(root.val + "->");
38             traversal(list, root.left, sb);
39             sb.delete(len, sb.length());
40         }
41         if (root.right != null) {
42             sb.append(root.val + "->");
43             traversal(list, root.right, sb);
44             sb.delete(len, sb.length());
45         }
46     }
47 }

Solution 2:

/**
 * Definition of TreeNode:
 * public class TreeNode {
 *     public int val;
 *     public TreeNode left, right;
 *     public TreeNode(int val) {
 *         this.val = val;
 *         this.left = this.right = null;
 *     }
 * }
 */

public class Solution {
    /**
     * @param root: the root of the binary tree
     * @return: all root-to-leaf paths
     */
    public List<String> binaryTreePaths(TreeNode root) {
        // write your code here
        List<String> list = new ArrayList<>();
        if(root == null) {
            return list;
        }
        traversal(list, root, "");
        return list;
    }

    private void traversal(List<String> list, TreeNode root, String str) {
        if (root == null) {
            return;
        }
        if (root.left == null && root.right == null) {
            String res = str + String.valueOf(root.val);
            list.add(res);
            return;
        }

        traversal(list, root.left, str + String.valueOf(root.val) + "->");
        traversal(list, root.right, str + String.valueOf(root.val) + "->" );
    }
}

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原文地址：https://www.cnblogs.com/xuanlu/p/15475237.html