• HDU 5023 A Corrupt Mayor's Performance Art 线段树区间更新+状态压缩


    Link:  http://acm.hdu.edu.cn/showproblem.php?pid=5023

      1 #include <cstdio>
      2 #include <cstring>
      3 #include <iostream>
      4 #include <algorithm>
      5 #include <vector>
      6 #include <string>
      7 #include <cmath>
      8 using namespace std;
      9 typedef __int64 LL;
     10 typedef unsigned int UINT;
     11 const int maxn = 1e6 + 5;
     12 
     13 #define LEFT(a,b) ((a) << (b))
     14 #define RIGHT(a,b) ((a) >> (b))
     15 
     16 struct node
     17 {
     18     UINT c,num;
     19     int l,r;
     20     node() {}
     21     node(const int t_l,const int t_r,const UINT t_c,const UINT t_num)
     22     {
     23         l = t_l,r = t_r;
     24         c = (1 << (t_c - 1));
     25         num = t_num;
     26     }
     27 }tree[4*maxn];
     28 
     29 void Init(const int p)
     30 {
     31     if(tree[p].l == tree[p].r) return ;
     32     int mid = RIGHT(tree[p].l + tree[p].r,1);
     33     tree[LEFT(p,1)] = node(tree[p].l,mid,2,1);
     34     tree[LEFT(p,1)+1] = node(mid+1,tree[p].r,2,1);
     35     Init(LEFT(p,1));
     36     Init(LEFT(p,1)+1);
     37 }
     38 void paste(const int p,const int t_l,const int t_r,const UINT t_c)
     39 {
     40     if(t_l > t_r) return ;
     41     if(t_l == tree[p].l && t_r == tree[p].r)
     42     {
     43         tree[p].c = t_c;
     44         tree[p].num = 1;
     45          return ;
     46     }
     47     int mid = (tree[p].l + tree[p].r) / 2;
     48     /*
     49     如果该段区间只有一种颜色,则要先把该段区间里的目标区间意外的区间涂成原来的颜色
     50     */
     51     if(1 == tree[p].num)
     52     {
     53         paste(LEFT(p,1),tree[p].l,mid,tree[p].c);
     54         paste(LEFT(p,1)+1,mid+1,tree[p].r,tree[p].c);
     55         /*
     56         if(t_r <= mid) paste(LEFT(p,1)+1,mid+1,tree[p].r,tree[p].c);
     57         else if(t_l <= mid && t_r > mid)
     58         {
     59             paste(LEFT(p,1),tree[p].l,t_l-1,tree[p].c);
     60             paste(LEFT(p,1)+1,t_r+1,tree[p].r,tree[p].c);
     61         }
     62         else if(t_l > mid) paste(LEFT(p,1),tree[p].l,mid,tree[p].c);
     63         */
     64     }
     65     if(t_r <= mid) paste(LEFT(p,1),t_l,t_r,t_c);
     66     else if(t_l <= mid && t_r > mid)
     67     {
     68         paste(LEFT(p,1),t_l,mid,t_c);
     69         paste(LEFT(p,1)+1,mid+1,t_r,t_c);
     70     }
     71     else if(t_l > mid) paste(LEFT(p,1)+1,t_l,t_r,t_c);
     72     
     73     tree[p].c = tree[LEFT(p,1)].c | tree[LEFT(p,1)+1].c;
     74     tree[p].num = 0;
     75     for(int i = 0;i <= 29;i++)
     76         if(tree[p].c & (1 << i))
     77             tree[p].num++;
     78 }
     79 
     80 void quire(const int p,const int t_l,const int t_r,UINT& t_c)
     81 {
     82     if(1 == tree[p].num || (tree[p].l == t_l && tree[p].r == t_r))
     83     {
     84         t_c |= tree[p].c;
     85         return ;
     86     }
     87     int mid = (tree[p].l + tree[p].r) / 2;
     88     if(t_r <= mid) quire(LEFT(p,1),t_l,t_r,t_c);
     89     else if(t_l <= mid && t_r > mid)
     90     {
     91         quire(LEFT(p,1),t_l,mid,t_c);
     92         quire(LEFT(p,1)+1,mid+1,t_r,t_c);
     93     }
     94     else if(t_l > mid) quire(LEFT(p,1)+1,t_l,t_r,t_c);
     95 }
     96 void print()
     97 {
     98     for(int i = 1;i <= 9;++i)
     99         printf("%d ",tree[i].c);
    100     puts("");
    101     for(int i = 1;i <= 9;i++)
    102         printf("%d ",tree[i].num);
    103     puts("");
    104 }
    105 int main()
    106 {
    107 //    freopen("in.txt","r",stdin);
    108     int n,m;
    109     while(scanf("%d%d",&n,&m),m+n)
    110     {
    111         tree[1] = node(1,n,2,1);
    112         Init(1);
    113         char oper[3];
    114         while(m--)
    115         {
    116             scanf("%s",oper);
    117             if('P' == oper[0])
    118             {
    119                 int x,y,c;
    120                 scanf("%d%d%d",&x,&y,&c);
    121                 paste(1,x,y,1 << (c - 1));
    122             //    print();
    123             }
    124             else
    125             {
    126                 int x,y;
    127                 UINT t_c = 0;
    128                 scanf("%d%d",&x,&y);
    129                 quire(1,x,y,t_c);
    130                 bool flag = false;
    131                 for(int i = 0;i <= 29;++i)
    132                     if(t_c & (1 << i))
    133                     {
    134                         if(flag) printf(" ");
    135                         flag = true;
    136                         printf("%d",i+1);
    137                     }
    138                 if(flag) puts("");
    139             //    print();
    140             }
    141         }
    142     }
    143     return 0;
    144 }
    View Code
  • 相关阅读:
    「多项式牛顿迭代」
    「多项式泰勒展开」
    接口测试构造数据的几种方法总结
    java spring框架的定时任务
    数据库索引
    selenium webdriver使用的一些小技巧(持续更新中)
    java http get和post请求
    测试攻城师的一点小开心
    selenium2支持无界面操作(HtmlUnit和PhantomJs)
    总结敏捷开发之Scrum
  • 原文地址:https://www.cnblogs.com/xiaxiaosheng/p/4746555.html
Copyright © 2020-2023  润新知