The numeric value of a lowercase character is defined as its position (1-indexed)
in the alphabet, so the numeric value of a
is 1
, the numeric value of b
is 2
, the numeric value of c
is 3
, and so on.
The numeric value of a string consisting of lowercase characters is defined as the sum of its characters' numeric values. For example, the numeric value of the string "abe"
is equal to 1 + 2 + 5 = 8
.
You are given two integers n
and k
. Return the lexicographically smallest string with length equal to n
and numeric value equal to k
.
Note that a string x
is lexicographically smaller than string y
if x
comes before y
in dictionary order, that is, either x
is a prefix of y
, or if i
is the first position such that x[i] != y[i]
, then x[i]
comes before y[i]
in alphabetic order.
Example 1:
Input: n = 3, k = 27 Output: "aay" Explanation: The numeric value of the string is 1 + 1 + 25 = 27, and it is the smallest string with such a value and length equal to 3.
Example 2:
Input: n = 5, k = 73 Output: "aaszz"
Constraints:
1 <= n <= 105
n <= k <= 26 * n
public String getSmallestString(int n, int k) { char[] ca = new char[n]; Arrays.fill(ca, 'a'); k -= n; // Guarantee each character value is at least 1. for (int i = n - 1; i >= 0 && k > 0; --i) { ca[i] += Math.min(25, k); k -= Math.min(k, 25); } return String.valueOf(ca); }
要lexical minimum,可以先建一个长度为n的char array,fill 'a', 然后从尾部开始往头部更新,从大到小安排。
很好很强大。
https://leetcode.com/problems/smallest-string-with-a-given-numeric-value/discuss/944594/JavaPython-3-O(n)-and-O(1)-codes-w-brief-explanation-and-analysis.