C# generic "where constraint" with "any generic type" definition?
Let me give example:
-
I have some generic class/interface definition:
interface IGenericCar< T > {...}
-
I have another class/interface that I want to relate with class above, for example:
interface IGarrage< TCar > : where TCar: IGenericCar< (**any type here**) > {...}
Basically, I want my generic IGarrage to be dependent on IGenericCar
, regardless if it's IGenericCar<int>
or IGenericCar<System.Color>
, because I don't have any dependency to that type.
回答1
There are typically 2 ways to achieve this.
Option1: Add another parameter to IGarrage
representing the T
which should be passed into the IGenericCar<T>
constraint:
interface IGarrage<TCar,TOther> where TCar : IGenericCar<TOther> { ... }
Option2: Define a base interface for IGenericCar<T>
which is not generic and constrain against that interface
interface IGenericCar { ... }
interface IGenericCar<T> : IGenericCar { ... }
interface IGarrage<TCar> where TCar : IGenericCar { ... }
评论:
回答2
Would it make any sense to do something like:
interface IGenericCar< T > {...}
interface IGarrage< TCar, TCarType >
where TCar: IGenericCar< TCarType > {...}
How to add a C# generic type constraint on another generic base class?
After checking that it compiles, I will upgrade it to an answer.
From your question and comments, you want the parameter to be Entity<Something>
. You do not need to use the parametrized types directly as a type, it can be use to parametrize a parameter.
So just do
public void Update(Entity<T1> entity) where ....
T
inside theIGarage<TCar>
? I can't see any possibility in option2. The best solution would be ifIGarage<TCar>
found typeT
by analysing typeTCar
.