• python 根据字典中的key,value进行排序


    #coding=utf-8
    
    import requests,json,collections,base64,datetime
    def sort(datas):
        data=json.dumps(datas)#dumps是将dict转化成str格式,loads是将str转化成dict格式。
        print u"data %s" % data
        data=json.loads(data)
        print  type(data)
        msg=data['msg'] #获取msg中key,value
        print msg
        print  type(msg)
        keys=msg.keys()
        msgkv={}
        for  k,v  in msg.items():
            msgkv[k]=v
        print msgkv
        kv=sorted(msgkv.items(),key=lambda item:item[0])#现在是按照key首字母进行排序,如果想按照value进行排序只需要将item[0],改为item[1]
        #print u"排序之后的字典 %s" % kv
        kv2={}
        mg=""
        for  k,v  in kv:
            kv2[k]=v
            mg=mg+k+'='+v+'&'
        mg=mg[:-1]
        #print u'连接符& %s'% mg
        print u"mg %s " % mg
        return mg
    msg={
        "msg": {
            "transTime": "20170110000000",
            "name": "张三",
            "accType": "00",
            "cardNo": "622586842111132567",
            "cnaps": "123456",
            "bankName": "银行",
            "certType": "00",
            "certNo": "350128199525362156",
            "phoneNo": "13665588962",
            "transAmt": "1",
            "currency": "CNY",
            "backUrl":"http://xxx/xxx",
            "proceedUse": "代扣",
            "businessCode": "10400"
        },
        "merchCode": "898000001000001",
        "orderId": "000000000000001",
        "transCode": "600101",
        "signature": "ImdJA+kA7FkDrEQuWSmbPqFkSF7UyWMX0/udozVP2grNrJVqgXcUBAbEP0jHPeSKenKw9a9lrBbLivTemIIuDk/Xywap/+9TYz5jQwmO/DegIuvHAi9JY6J3orSCl0eHM+7wGydxNnqoOBZcST1GzzYgHBs9fmWYWtpkX6cnFBOfJ/vFXNbiSzI8byNSae2MMbn7RSr9ymCNxVrBIPtN9x6WtDtrTGo/5iW1ZOSb5mqxyA8dVnebTjwWEnGmdu2"
    }
    mg1=sort(msg)
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  • 原文地址:https://www.cnblogs.com/wangxiaoqun/p/9963359.html
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