• lca最短公共祖先模板(hdu2586)


    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2586

    #include<iostream> 
    #include<cstdio> 
    #include<cmath>
    #include<queue>
    #include<vector>
    #include<string.h>
    #include<cstring>
    #include<algorithm>
    #include<set>
    #include<map>
    #include<fstream>
    #include<cstdlib>
    #include<ctime>
    #include<list>
    #include<climits>
    #include<bitset>
    using namespace std;
    #define fio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    #define fopen freopen("input.txt", "r", stdin);freopen("output.txt", "w", stdout);
    #define scd(a) scanf("%d",&a)
    #define scf(a) scanf("%lf",&a)
    #define scl(a) scanf("%lld",&a)
    #define sci(a) scanf("%I64d",&a)
    #define scs(a) scanf("%s",a)
    #define left asfdasdasdfasdfsdfasfsdfasfdas1
    #define tan asfdasdasdfasdfasfdfasfsdfasfdas
    typedef long long ll;
    typedef unsigned int un;
    const int desll[4][2]={{0,1},{0,-1},{1,0},{-1,0}};
    const ll mod=1e9+7;
    const int maxn=4e4+7;
    const int maxm=3e8+7;
    const double eps=1e-4;
    int m,n;
    
    struct node
    {
        int b,nex,c;
    }no[maxn*2];
    int head[maxn],sz=0;
    int add(int a,int b,int c){
        no[sz].b=b;
        no[sz].c=c;
        no[sz].nex=head[a];
        head[a]=sz++;
    }
    int father[maxn],tan[maxn*2][30],dep[maxn];
    int ar[maxn*2],le,in[maxn];
    ll dis[maxn];
    void dfs1(int u,int pre){
        for(int i=head[u];i!=-1;i=no[i].nex){
            int v=no[i].b;
            if(v==pre)continue;
            dis[v]=dis[u]+no[i].c;
            father[v]=u;
            dep[v]=dep[u]+1;
            ar[le++]=u;
            dfs1(v,u);
        }
        in[u]=le;
        ar[le++]=u;
    }
    void init()
    {
        memset(tan,0,sizeof(tan));
        for(int i=0;i<le;i++){
            tan[i][0]=ar[i];
        }
        for(int j=1;j<20;j++){
            for(int i=le-1;i>=0;i--){
                if(i+(1<<j)-1>=le)continue;
                int x=tan[i][j-1],y=tan[i+(1<<(j-1))][j-1];
                if(dep[x]<dep[y])tan[i][j]=x;
                else tan[i][j]=y;
                //cout<<i<<" "<<j<<" "<<tan[i][j]<<endl;
            }
        }
    }
    int sameFather(int a,int b)
    {
        a=in[a];
        b=in[b];
        if(a>b)swap(a,b);
        int res=floor(log(b-a+1)/log(2));
        int x=tan[a][res],y=tan[b-(1<<res)+1][res];
        if(dep[x]<dep[y])return x;
        else return y;
    }
    
    int main()
    {
        int t;scd(t);
        while(t--){
            scd(n);scd(m);
            memset(head,-1,sizeof(head));sz=0;
            for(int i=1;i<n;i++){
                int a,b,c;
                scd(a);scd(b);scd(c);
                add(a,b,c);
                add(b,a,c);
            }
            memset(dis,0,sizeof(dis));
            memset(dep,0,sizeof(dep));
            dep[1]=1;
            dfs1(1,0);
            father[1]=0;
            init();
            for(int i=0;i<m;i++){
                int a,b;
                scd(a);scd(b);
                int x=sameFather(a,b);
                printf("%d
    ",dis[a]+dis[b]-2*dis[x]);
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/wa007/p/9697104.html
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