• 一个项目涉及到的50个Sql语句(下)


    --24、查询学生平均成绩及其名次
    --
    24.1 查询学生的平均成绩并进行排名,sql 2000用子查询完成,分平均成绩重复时保留名次空缺和不保留名次空缺两种。
    select t1.* , px = (select count(1) from
    (
     
    select m.S# [学生编号] ,
             m.Sname
    [学生姓名] ,
            
    isnull(cast(avg(score) as decimal(18,2)),0) [平均成绩]
     
    from Student m left join SC n on m.S# = n.S#
     
    group by m.S# , m.Sname
    ) t2
    where 平均成绩 > t1.平均成绩) + 1 from
    (
     
    select m.S# [学生编号] ,
             m.Sname
    [学生姓名] ,
            
    isnull(cast(avg(score) as decimal(18,2)),0) [平均成绩]
     
    from Student m left join SC n on m.S# = n.S#
     
    group by m.S# , m.Sname
    ) t1
    order by px

    select t1.* , px = (select count(distinct 平均成绩) from
    (
     
    select m.S# [学生编号] ,
             m.Sname
    [学生姓名] ,
            
    isnull(cast(avg(score) as decimal(18,2)),0) [平均成绩]
     
    from Student m left join SC n on m.S# = n.S#
     
    group by m.S# , m.Sname
    ) t2
    where 平均成绩 >= t1.平均成绩) from
    (
     
    select m.S# [学生编号] ,
             m.Sname
    [学生姓名] ,
            
    isnull(cast(avg(score) as decimal(18,2)),0) [平均成绩]
     
    from Student m left join SC n on m.S# = n.S#
     
    group by m.S# , m.Sname
    ) t1
    order by px
    --24.2 查询学生的平均成绩并进行排名,sql 2005用rank,DENSE_RANK完成,分平均成绩重复时保留名次空缺和不保留名次空缺两种。
    select t.* , px = rank() over(order by [平均成绩] desc) from
    (
     
    select m.S# [学生编号] ,
             m.Sname
    [学生姓名] ,
            
    isnull(cast(avg(score) as decimal(18,2)),0) [平均成绩]
     
    from Student m left join SC n on m.S# = n.S#
     
    group by m.S# , m.Sname
    ) t
    order by px

    select t.* , px = DENSE_RANK() over(order by [平均成绩] desc) from
    (
     
    select m.S# [学生编号] ,
             m.Sname
    [学生姓名] ,
            
    isnull(cast(avg(score) as decimal(18,2)),0) [平均成绩]
     
    from Student m left join SC n on m.S# = n.S#
     
    group by m.S# , m.Sname
    ) t
    order by px
     
    --25、查询各科成绩前三名的记录
    --
    25.1 分数重复时保留名次空缺
    select m.* , n.C# , n.score from Student m, SC n where m.S# = n.S# and n.score in
    (
    select top 3 score from sc where C# = n.C# order by score desc) order by n.C# , n.score desc
    --25.2 分数重复时不保留名次空缺,合并名次
    --
    sql 2000用子查询实现
    select * from (select t.* , px = (select count(distinct score) from SC where C# = t.C# and score >= t.score) from sc t) m where px between 1 and 3 order by m.c# , m.px
    --sql 2005用DENSE_RANK实现
    select * from (select t.* , px = DENSE_RANK() over(partition by c# order by score desc) from sc t) m where px between 1 and 3 order by m.C# , m.px

    --26、查询每门课程被选修的学生数
    select c# , count(S#)[学生数] from sc group by C#

    --27、查询出只有两门课程的全部学生的学号和姓名
    select Student.S# , Student.Sname
    from Student , SC
    where Student.S# = SC.S#
    group by Student.S# , Student.Sname
    having count(SC.C#) = 2
    order by Student.S#

    --28、查询男生、女生人数
    select count(Ssex) as 男生人数 from Student where Ssex = N''
    select count(Ssex) as 女生人数 from Student where Ssex = N''
    select sum(case when Ssex = N'' then 1 else 0 end) [男生人数],sum(case when Ssex = N'' then 1 else 0 end) [女生人数] from student
    select case when Ssex = N'' then N'男生人数' else N'女生人数' end [男女情况] , count(1) [人数] from student group by case when Ssex = N'' then N'男生人数' else N'女生人数' end

    --29、查询名字中含有"风"字的学生信息
    select * from student where sname like N'%风%'
    select * from student where charindex(N'' , sname) > 0

    --30、查询同名同性学生名单,并统计同名人数
    select Sname [学生姓名], count(*) [人数] from Student group by Sname having count(*) > 1

    --31、查询1990年出生的学生名单(注:Student表中Sage列的类型是datetime)
    select * from Student where year(sage) = 1990
    select * from Student where datediff(yy,sage,'1990-01-01') = 0
    select * from Student where datepart(yy,sage) = 1990
    select * from Student where convert(varchar(4),sage,120) = '1990'

    --32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列
    select m.C# , m.Cname , cast(avg(n.score) as decimal(18,2)) avg_score
    from Course m, SC n
    where m.C# = n.C#   
    group by m.C# , m.Cname
    order by avg_score desc, m.C# asc

    --33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩
    select a.S# , a.Sname , cast(avg(b.score) as decimal(18,2)) avg_score
    from Student a , sc b
    where a.S# = b.S#
    group by a.S# , a.Sname
    having cast(avg(b.score) as decimal(18,2)) >= 85
    order by a.S#

    --34、查询课程名称为"数学",且分数低于60的学生姓名和分数
    select sname , score
    from Student , SC , Course
    where SC.S# = Student.S# and SC.C# = Course.C# and Course.Cname = N'数学' and score < 60

    --35、查询所有学生的课程及分数情况;
    select Student.* , Course.Cname , SC.C# , SC.score 
    from Student, SC , Course
    where Student.S# = SC.S# and SC.C# = Course.C#
    order by Student.S# , SC.C#

    --36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数;
    select Student.* , Course.Cname , SC.C# , SC.score 
    from Student, SC , Course
    where Student.S# = SC.S# and SC.C# = Course.C# and SC.score >= 70
    order by Student.S# , SC.C#

    --37、查询不及格的课程
    select Student.* , Course.Cname , SC.C# , SC.score 
    from Student, SC , Course
    where Student.S# = SC.S# and SC.C# = Course.C# and SC.score < 60
    order by Student.S# , SC.C#

    --38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名;
    select Student.* , Course.Cname , SC.C# , SC.score 
    from Student, SC , Course
    where Student.S# = SC.S# and SC.C# = Course.C# and SC.C# = '01' and SC.score >= 80
    order by Student.S# , SC.C#

    --39、求每门课程的学生人数
    select Course.C# , Course.Cname , count(*) [学生人数]
    from Course , SC
    where Course.C# = SC.C#
    group by  Course.C# , Course.Cname
    order by Course.C# , Course.Cname

    --40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩
    --
    40.1 当最高分只有一个时
    select top 1 Student.* , Course.Cname , SC.C# , SC.score 
    from Student, SC , Course , Teacher
    where Student.S# = SC.S# and SC.C# = Course.C# and Course.T# = Teacher.T# and Teacher.Tname = N'张三'
    order by SC.score desc
    --40.2 当最高分出现多个时
    select Student.* , Course.Cname , SC.C# , SC.score 
    from Student, SC , Course , Teacher
    where Student.S# = SC.S# and SC.C# = Course.C# and Course.T# = Teacher.T# and Teacher.Tname = N'张三' and
    SC.score
    = (select max(SC.score) from SC , Course , Teacher where SC.C# = Course.C# and Course.T# = Teacher.T# and Teacher.Tname = N'张三')

    --41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩
    --
    方法1
    select m.* from SC m ,(select C# , score from SC group by C# , score having count(1) > 1) n
    where m.C#= n.C# and m.score = n.score order by m.C# , m.score , m.S#
    --方法2
    select m.* from SC m where exists (select 1 from (select C# , score from SC group by C# , score having count(1) > 1) n
    where m.C#= n.C# and m.score = n.score) order by m.C# , m.score , m.S#

    --42、查询每门功成绩最好的前两名
    select t.* from sc t where score in (select top 2 score from sc where C# = T.C# order by score desc) order by t.C# , t.score desc

    --43、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列 
    select Course.C# , Course.Cname , count(*) [学生人数]
    from Course , SC
    where Course.C# = SC.C#
    group by  Course.C# , Course.Cname
    having count(*) >= 5
    order by [学生人数] desc , Course.C#

    --44、检索至少选修两门课程的学生学号
    select student.S# , student.Sname
    from student , SC
    where student.S# = SC.S#
    group by student.S# , student.Sname
    having count(1) >= 2
    order by student.S#

    --45、查询选修了全部课程的学生信息
    --
    方法1 根据数量来完成
    select student.* from student where S# in
    (
    select S# from sc group by S# having count(1) = (select count(1) from course))
    --方法2 使用双重否定来完成
    select t.* from student t where t.S# not in
    (
     
    select distinct m.S# from
      (
       
    select S# , C# from student , course
      ) m
    where not exists (select 1 from sc n where n.S# = m.S# and n.C# = m.C#)
    )
    --方法3 使用双重否定来完成
    select t.* from student t where not exists(select 1 from
    (
     
    select distinct m.S# from
      (
       
    select S# , C# from student , course
      ) m
    where not exists (select 1 from sc n where n.S# = m.S# and n.C# = m.C#)
    ) k
    where k.S# = t.S#
    )

    --46、查询各学生的年龄
    --
    46.1 只按照年份来算
    select * , datediff(yy , sage , getdate()) [年龄] from student
    --46.2 按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一
    select * , case when right(convert(varchar(10),getdate(),120),5) < right(convert(varchar(10),sage,120),5) then datediff(yy , sage , getdate()) - 1 else datediff(yy , sage , getdate()) end [年龄] from student

    --47、查询本周过生日的学生
    select * from student where datediff(week,datename(yy,getdate()) + right(convert(varchar(10),sage,120),6),getdate()) = 0

    --48、查询下周过生日的学生
    select * from student where datediff(week,datename(yy,getdate()) + right(convert(varchar(10),sage,120),6),getdate()) = -1

    --49、查询本月过生日的学生
    select * from student where datediff(mm,datename(yy,getdate()) + right(convert(varchar(10),sage,120),6),getdate()) = 0

    --50、查询下月过生日的学生
    select * from student where datediff(mm,datename(yy,getdate()) + right(convert(varchar(10),sage,120),6),getdate()) = -1

    drop table  Student,Course,Teacher,SC

  • 相关阅读:
    VB程序破解常用函数
    去VB程序NAG窗口方法-4C法
    error LNK2005: _DllMain@12 已经在 XXXX.obj 中定义
    汇编中的test和cmp指令
    OD保存修改后的数据到EXE
    C++ 异常捕获 try 和 __try的区别
    CListCtrl选中行
    WindowsAPI解析IAT地址
    Usaco 4.3.1 Buy Low, Buy Lower 逢低吸纳详细解题报告
    全国青少年信息学奥林匹克分区联赛(N)竞赛大纲
  • 原文地址:https://www.cnblogs.com/vipk/p/1742601.html
Copyright © 2020-2023  润新知