• 2015 多校第四场


    一定要补上  o(╯□╰)o。。

    5327 签到。。

     1 /*Author :usedrose  */
     2 /*Created Time :2015/7/31 22:36:32*/
     3 /*File Name :2.cpp*/
     4 #include <cstdio>
     5 #include <iostream>
     6 #include <algorithm>
     7 #include <sstream>
     8 #include <cstdlib>
     9 #include <cstring>
    10 #include <climits>
    11 #include <vector>
    12 #include <string>
    13 #include <ctime>
    14 #include <cmath>
    15 #include <deque>
    16 #include <queue>
    17 #include <stack>
    18 #include <set>
    19 #include <map>
    20 #define INF 0x3f3f3f3f
    21 #define eps 1e-8
    22 #define pi acos(-1.0)
    23 #define MAXN 1110
    24 #define OK cout << "ok" << endl;
    25 #define o(a) cout << #a << " = " << a << endl
    26 #define o1(a,b) cout << #a << " = " << a << "  " << #b << " = " << b << endl
    27 using namespace std;
    28 typedef long long LL;
    29 
    30 bool is(int x)
    31 {
    32     int a[10];
    33     memset(a, 0, sizeof(a));
    34     while (x) {
    35         int k = x%10;
    36         if (a[k]) return false;
    37         a[k]++;
    38         x /= 10;
    39     }
    40     return true;
    41 }
    42 
    43 int num[100010];
    44 
    45 void init()
    46 {
    47     for (int i = 1;i <= 100005; ++ i) {
    48         num[i] = num[i-1] + is(i);
    49     }
    50 }
    51 
    52 int main()
    53 {
    54     //freopen("data.in","r",stdin);
    55     //freopen("data.out","w",stdout);
    56     cin.tie(0);
    57     ios::sync_with_stdio(false);
    58     init();
    59     int T;
    60     cin >> T;
    61     while (T--) {
    62         int l, r;
    63         cin >> l >> r;
    64         cout << num[r] - num[l-1] << endl;
    65     }
    66     return 0;
    67 }
    View Code

    5328 再签一次。。

     1 #include <stdio.h>
     2 #include <algorithm>
     3 
     4 #define MAXN 1000005
     5 
     6 int a[MAXN];
     7 
     8 inline void solve()
     9 {
    10     int n;
    11     scanf("%d",&n);
    12     int i;
    13     for (i=1;i<=n;i++) {
    14         scanf("%d",a+i);
    15     }
    16     int ans=std::min(2,n);
    17     
    18     int l=1;
    19     for (i=3;i<=n;i++) {
    20         bool f= 2*a[i-1]==a[i-2]+a[i];
    21         if (!f) l=i-1;
    22         ans=std::max(ans,i-l+1);
    23     }
    24     
    25     l=1;
    26     for (i=3;i<=n;i++) {
    27         bool f= 1LL*a[i-1]*a[i-1]==1LL*a[i-2]*a[i];
    28         if (!f) l=i-1;
    29         ans=std::max(ans,i-l+1);
    30     }
    31     
    32     printf("%d
    ",ans);
    33 }
    34 
    35 int main()
    36 {
    37     int T;
    38     scanf("%d",&T);
    39     int i;
    40     for (i=1;i<=T;i++) {
    41         solve();
    42     }
    43 }
    View Code

    hdu5335

    主要是贪心..

     1 /*Author :usedrose  */
     2 /*Created Time :2015/8/1 9:29:16*/
     3 /*File Name :2.cpp*/
     4 #pragma comment(linker, "/STACK:1024000000,1024000000") 
     5 #include <cstdio>
     6 #include <iostream>
     7 #include <algorithm>
     8 #include <sstream>
     9 #include <cstdlib>
    10 #include <cstring>
    11 #include <climits>
    12 #include <vector>
    13 #include <string>
    14 #include <ctime>
    15 #include <cmath>
    16 #include <deque>
    17 #include <queue>
    18 #include <stack>
    19 #include <set>
    20 #include <map>
    21 #define INF 0x3f3f3f3f
    22 #define eps 1e-8
    23 #define pi acos(-1.0)
    24 #define MAXN 1110
    25 #define OK cout << "ok" << endl;
    26 #define o(a) cout << #a << " = " << a << endl
    27 #define o1(a,b) cout << #a << " = " << a << "  " << #b << " = " << b << endl
    28 using namespace std;
    29 typedef long long LL;
    30 
    31 int T, n, m, tx[4] = {0, 0, 1, -1}, ty[4] = {1, -1, 0, 0};
    32 char S[1100][1100];
    33 bool used[1100][1100];
    34 int xx[1100000], yy[1100000];
    35 
    36 void bfs()
    37 {
    38     memset(used, false, sizeof(used));
    39     used[1][1] = true;
    40     int q = 1, h = 1;
    41     xx[q] = yy[q] = 1;
    42     for (;q <= h; ++ q) 
    43         if (S[xx[q]][yy[q]] == '0') {
    44             for (int i = 0;i < 4; ++ i) {
    45                 int X = xx[q] + tx[i];
    46                 int Y = yy[q] + ty[i];
    47                 if (X > 0 && X <= n && Y > 0 && Y <= m && !used[X][Y]) {
    48                     h++;
    49                     xx[h] = X;
    50                     yy[h] = Y;
    51                     used[X][Y] = true;
    52                 }
    53             }        
    54         }
    55         if (used[n][m] && S[n][m] == '0') {
    56             puts("0");
    57             return;
    58         }
    59     int ma = 0;
    60     for (int i = 1;i <= n; ++ i)
    61         for (int j = 1;j <= m; ++ j)
    62             if (used[i][j])
    63                 ma = max(ma, i + j);
    64     printf("1");
    65     for (int i = ma; i < n+m; ++ i) {
    66         char mi = '1';
    67         for (int j = 1;j <= n; ++ j) 
    68             if (1 <= i - j && i-j <= m && used[j][i-j]) {
    69                 mi = min(mi, S[j+1][i-j]);
    70                 mi = min(mi, S[j][i-j+1]);
    71             }
    72         printf("%c", mi);
    73         for (int j = 1;j <= n; ++ j)
    74             if (1 <= i - j && i -j <= m && used[j][i-j]) {
    75                 if (S[j+1][i-j] == mi) used[j+1][i-j] = true;
    76                 if (S[j][i-j+1] == mi) used[j][i-j+1] = true;
    77             }
    78     }
    79     puts("");
    80 }
    81 
    82 int main()
    83 {
    84     scanf("%d", &T);
    85     while (T--) {
    86         scanf("%d%d", &n, &m);
    87         for (int i = 1;i <= n; ++ i)
    88             scanf("%s", S[i]+1);
    89         for (int i = 0;i <= n+1; ++ i) 
    90             S[i][0] = '2', S[i][m+1] = '2';
    91         for (int i = 0;i <= m + 1; ++ i)
    92             S[0][i] = '2', S[n+1][i] = '2';
    93         bfs();
    94     }
    95     return 0;
    96 }
    View Code
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  • 原文地址:https://www.cnblogs.com/usedrosee/p/4693004.html
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