Problem 1
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
C++:
#include <iostream> using namespace std; int main() { int n, sum; while(cin >> n) { sum = 0; for(int i=1; i<n; i++) if(i % 3 == 0 || i % 5 == 0) sum += i; cout << sum << endl; } return 0; }
Python:
print(sum([x for x in range(1000) if x%3==0 or x%5==0]))