Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
经典动态规划。
状态方程: dp[i][j] = Math.min(dp[i - 1][j], dp[i][j - 1]) + grid[i][j];
public class Solution { public int minPathSum(int[][] grid) { if(grid == null) { return 0; } int rows = grid.length; int cols = grid[0].length; int[][] dp = new int[rows][cols]; dp[0][0] = grid[0][0]; // initialize the first row for(int i = 1; i < cols; i++) { dp[0][i] = dp[0][i - 1] + grid[0][i]; } //initialize the first col for(int i = 1; i < rows; i++) { dp[i][0] = dp[i - 1][0] + grid[i][0]; } for(int i = 1; i < rows; i++) { for(int j = 1; j < cols; j++) { dp[i][j] = Math.min(dp[i - 1][j], dp[i][j - 1]) + grid[i][j]; } } return dp[rows - 1][cols - 1]; } }