• [Swift]LeetCode1124. 表现良好的最长时间段 | Longest Well-Performing Interval


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    We are given hours, a list of the number of hours worked per day for a given employee.

    A day is considered to be a tiring day if and only if the number of hours worked is (strictly) greater than 8.

    well-performing interval is an interval of days for which the number of tiring days is strictly larger than the number of non-tiring days.

    Return the length of the longest well-performing interval. 

    Example 1:

    Input: hours = [9,9,6,0,6,6,9]
    Output: 3
    Explanation: The longest well-performing interval is [9,9,6]. 

    Constraints:

    • 1 <= hours.length <= 10000
    • 0 <= hours[i] <= 16

    给你一份工作时间表 hours,上面记录着某一位员工每天的工作小时数。

    我们认为当员工一天中的工作小时数大于 8 小时的时候,那么这一天就是「劳累的一天」。

    所谓「表现良好的时间段」,意味在这段时间内,「劳累的天数」是严格 大于「不劳累的天数」。

    请你返回「表现良好时间段」的最大长度。 

    示例 1:

    输入:hours = [9,9,6,0,6,6,9]
    输出:3
    解释:最长的表现良好时间段是 [9,9,6]。 

    提示:

    • 1 <= hours.length <= 10000
    • 0 <= hours[i] <= 16

    140ms
     1 class Solution {
     2     func longestWPI(_ hours: [Int]) -> Int {
     3         var maxInterval = 0
     4         var wellDays = 0
     5         var dict = [Int: Int]()
     6         
     7         for i in 0..<hours.count {
     8             wellDays += hours[i] > 8 ? 1 : -1
     9             if(wellDays >= 1) {
    10                 maxInterval = max(maxInterval, i + 1);
    11             }
    12 
    13             if dict[wellDays] != nil {
    14                 guard let maxSum = dict[wellDays-1] else { continue }
    15                 maxInterval = max(maxInterval, i-maxSum)
    16             } else {
    17                 dict[wellDays] = i
    18             }
    19         }
    20         if maxInterval == 0 {
    21             maxInterval = hours.filter{$0 > 8}.count >= 1 ? 1 : 0
    22         }
    23         return maxInterval
    24     }
    25 }

    148ms

     1 class Solution {
     2     func longestWPI(_ hours: [Int]) -> Int {
     3         var result = 0
     4         var score = 0 
     5         var n = hours.count 
     6         var seen = [Int: Int]()
     7         
     8         for i in 0..<n {
     9             score += hours[i] > 8 ? 1 : -1
    10             if score > 0 {
    11                 result = i + 1
    12             } else {
    13                 if seen[score] == nil {
    14                     seen[score] = i 
    15                 }
    16                 if let idx = seen[score - 1] {
    17                     result = max(result, i - idx)
    18                 }
    19             }
    20         }
    21         return result
    22     }
    23 }

    164ms

     1 class Solution {
     2     func longestWPI(_ hours: [Int]) -> Int {
     3     var memo : [Int:Int] = [0:-1]
     4     var maxLength = 0
     5     var countAboveTiringDays = 0
     6     for i in 0..<hours.count {
     7         if hours[i] > 8 {
     8             countAboveTiringDays += 1
     9         } else {
    10             countAboveTiringDays -= 1
    11         }
    12 
    13         // if the count is positive, then it is just the number of days
    14         if countAboveTiringDays > 0 {
    15             maxLength = i + 1
    16         } else {
    17         
    18             if memo[countAboveTiringDays - 1] != nil {
    19                 maxLength = max(maxLength, i - memo[countAboveTiringDays - 1]!)
    20             }
    21             
    22             if memo[countAboveTiringDays] == nil
    23             {
    24                 memo[countAboveTiringDays] = i
    25             }
    26 
    27         }
    28     }
    29     return maxLength
    30     }
    31 }

    1900ms

     1 class Solution {
     2     func longestWPI(_ hours: [Int]) -> Int {
     3         var ans = 0
     4         let size  = hours.count
     5         let hoursCopy = hours.map { (val) -> Int in
     6             val > 8 ? 1 : -1
     7         }
     8         
     9         var sum = Array<Int>(repeating: 0, count: size + 1)
    10         for i in 0..<size {
    11             sum[i + 1] = sum[i] + hoursCopy[i]
    12         }
    13         for i in 0..<size {
    14             var j = size
    15             while j > i && j - i > ans  {
    16                 if  sum[i] < sum[j] {
    17                     ans = j - i
    18                 }
    19                 j -= 1
    20             }
    21         }
    22         return ans
    23     }
    24 }

    Runtime: 3896 ms

    Memory Usage: 21.2 MB
     1 class Solution {
     2     func longestWPI(_ hours: [Int]) -> Int {
     3         var hours = hours
     4         for i in 0..<hours.count
     5         {
     6             if hours[i] > 8 {hours[i] = 1}
     7             else {hours[i] = -1}
     8         }
     9         var ans:Int = 0
    10         for i in 0..<hours.count
    11         {
    12             var bal:Int = 0
    13             var cur:Int = -1
    14             for j in i..<hours.count
    15             {
    16                 bal += hours[j]
    17                 if bal > 0
    18                 {
    19                     cur = j
    20                 }
    21             }
    22             ans = max(ans, cur - i + 1)
    23         }
    24         return ans        
    25     }
    26 }
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  • 原文地址:https://www.cnblogs.com/strengthen/p/11179548.html
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