白菜刷LeetCode记-704. Binary Search

简单题，直接是用来复习二分查找的。题目如下：

代码如下：

/**
 * @param {number[]} nums
 * @param {number} target
 * @return {number}
 */
var search = function(nums, target) {
    let len = nums.length;
    let lp = 0, rp = len -1;
    let mid = parseInt((lp + rp)/2);
    
    while(lp <= rp){
        if(target == nums[mid]){
            return mid;
        }else if(target < nums[mid]){
            rp = mid - 1;
        }else{
            lp = mid + 1;
        }
        
        mid = parseInt((lp+rp)/2);
    }
    
    return -1;
    
    
    
}