• POJ 3801 有上下界最小流


       1:  /**
       2:      POJ 3801 有上下界的最小流
       3:  
       4:  1、对supersrc到supersink 求一次最大流,记为f1。(在有源汇的情况下,先使整个网络趋向必须边尽量满足的情况)
       5:  2、添加一条边sink -> src,流量上限为INF,这条边记为p。(构造无源汇网络)
       6:  3、对supersrc到supersink再次求最大流,记为f2,这里判断是否为可行流。(要判断可行,必须先构造无源汇网络流,因此要再次求最大流)
       7:  
       8:      此网络流的最小流即为 sink -> src 的流量
       9:  */
      10:   
      11:  #include<iostream>
      12:  #include<cmath>
      13:  #include<memory>
      14:  #include <string.h>
      15:  #include <cstdio>
      16:  #include <vector>
      17:  using namespace std;
      18:   
      19:  #define V 150      // vertex
      20:  #define E  (V*V)     // edge
      21:  #define INF 0x3F3F3F3F  // 1061109567
      22:   
      23:  int i,j,k;
      24:  #define REP(i,n) for((i)=0;(i)<(int)(n);(i)++)
      25:  #define snuke(c,itr) for(__typeof((c).begin()) itr=(c).begin();itr!=(c).end();itr++)
      26:   
      27:  struct MaxFlow
      28:  {
      29:      struct Edge
      30:      {
      31:          int v, w, next;     //w for capicity
      32:          int lb,up;
      33:      } edge[E];
      34:   
      35:      int head[V];          // head[u]表示顶点u第一条邻接边的序号, 若head[u] = -1, u没有邻接边
      36:      int e;                // the index of the edge
      37:      int src, sink;
      38:      int net[V];              // 流入此节点的流的下界和 - 流出此节点的流的下界和,对于带上下界的来进行使用
      39:   
      40:   
      41:      void addedge(int  u, int v, int w, int lb = 0, int up = INF, int rw = 0)
      42:      {
      43:          edge[e].v = v;
      44:          edge[e].w= w;
      45:          edge[e].next = head[u];
      46:          edge[e].lb = lb, edge[e].up = up;
      47:          head[u] = e++;
      48:          // reverse edge  v -> u
      49:          edge[e].v = u;
      50:          edge[e].w = rw;
      51:          edge[e].lb = lb, edge[e].up = up;
      52:          edge[e].next = head[v];
      53:          head[v] = e++;
      54:      }
      55:   
      56:      int ISAP(int VertexNum )
      57:      {
      58:          int u, v, max_flow, aug, min_lev;
      59:          int curedge[V], parent[V], level[V];
      60:          int count[V], augment[V];
      61:   
      62:          memset(level, 0, sizeof(level));
      63:          memset(count, 0, sizeof(count));
      64:          REP(i,VertexNum+1) curedge[i] = head[i];
      65:          max_flow = 0;
      66:          augment[src] = INF;
      67:          parent[src] = -1;
      68:          u = src;
      69:   
      70:          while (level[src] < VertexNum)
      71:          {
      72:              if (u == sink)
      73:              {
      74:                  max_flow += augment[sink];
      75:                  aug = augment[sink];
      76:                  for (v = parent[sink]; v != -1; v = parent[v])
      77:                  {
      78:                      i = curedge[v];
      79:                      edge[i].w  -= aug;
      80:                      edge[i^1].w  += aug;
      81:                      augment[edge[i].v] -= aug;
      82:                      if (edge[i].w == 0) u = v;
      83:                  }
      84:              }
      85:              for (i = curedge[u]; i != -1; i = edge[i].next)
      86:              {
      87:                  v = edge[i].v;
      88:                  if (edge[i].w > 0 && level[u] == (level[v]+1))
      89:                  {
      90:                      augment[v] = min(augment[u], edge[i].w);
      91:                      curedge[u] = i;
      92:                      parent[v] = u;
      93:                      u = v;
      94:                      break;
      95:                  }
      96:              }
      97:              if (i == -1)
      98:              {
      99:                  if (--count[level[u]] == 0) break;
     100:                  curedge[u] = head[u];
     101:                  min_lev = VertexNum;
     102:                  for (i = head[u]; i != -1; i = edge[i].next)
     103:                      if (edge[i].w > 0)
     104:                          min_lev = min(level[edge[i].v], min_lev);
     105:                  level[u] = min_lev + 1;
     106:                  count[level[u]]++;
     107:                  if (u != src ) u = parent[u];
     108:              }
     109:          }
     110:          return max_flow;
     111:      }
     112:      void solve()
     113:      {
     114:          int n, m;
     115:          while (scanf("%d %d", &n, &m) != EOF)
     116:          {
     117:              if (n+m == 0) break;
     118:              e = 0;
     119:              memset(head, -1, sizeof(head));
     120:              memset(net, 0, sizeof(net));
     121:   
     122:              int s = n+1, t = n+2;
     123:              src = n+3, sink = n+4;
     124:              char a[5], b[5];
     125:              int c;
     126:              while (m--)
     127:              {
     128:                  scanf("%s %s %d", a, b, &c);
     129:                  int u, v;
     130:                  if (a[0] == '+') u = s;
     131:                  else sscanf(a, "%d", &u);   // 注意这里读取信息
     132:                  if (b[0] == '-') v = t;
     133:                  else sscanf(b, "%d", &v);
     134:                  net[v] += c, net[u] -= c;
     135:                  addedge(u,v,INF,c, INF);
     136:              }
     137:              vector<int> CE;
     138:              for(int i=1; i<=n+2; i++)
     139:              {
     140:                  if(net[i] >=0)
     141:                  {
     142:                      CE.push_back(e);
     143:                      addedge(src, i, net[i]);
     144:                  }
     145:                  else
     146:                  {
     147:                      CE.push_back(e);
     148:                      addedge(i, sink, -net[i]);
     149:                  }
     150:              }
     151:              int flow = 0;
     152:              flow =  ISAP(n+4);
     153:              int p = e;
     154:              addedge(t, s, INF, 0, INF);
     155:              flow += ISAP(n+4);
     156:              bool flag = true;
     157:              for(int i= 0; i< CE.size(); i++)
     158:              {
     159:                  if(edge[CE[i]].w !=0)
     160:                  {
     161:                      flag = false;
     162:                      break;
     163:                  }
     164:              }
     165:              if (!flag)
     166:                  printf("impossible
    ");
     167:              else
     168:                  printf("%d
    ", edge[p^1].w);
     169:          }
     170:      }
     171:  } sap;
     172:   
     173:  int main()
     174:  {
     175:  //    freopen("1.txt","r",stdin);
     176:      sap.solve();
     177:      return 0;
     178:  }
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  • 原文地址:https://www.cnblogs.com/sosi/p/3716716.html
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