• FFT 模板


    FFT,这份代码在51nod跑的非常快,赶紧扒下来!

    //FFT 大整数乘法
    #include<cstdio>
    #include<cmath>
    #include<cstring>
    #include<algorithm>
    
    using namespace std;
    
    
    const int N = 500005;
    const double pi = acos(-1.0);
    
    char s1[N],s2[N];
    int len,res[N];
    
    struct Complex
    {
        double r,i;
    	Complex(double r=0,double i=0):r(r),i(i) {};
    	Complex operator+(const Complex &rhs)
    	{
    		return Complex(r + rhs.r,i + rhs.i);
    	}
    	Complex operator-(const Complex &rhs)
    	{
    		return Complex(r - rhs.r,i - rhs.i);
    	}
    	Complex operator*(const Complex &rhs)
    	{
    		return Complex(r*rhs.r - i*rhs.i,i*rhs.r + r*rhs.i);
    	}
    } va[N],vb[N];
    
    void rader(Complex F[],int len)	//len = 2^M,reverse F[i] with  F[j] j为i二进制反转
    {
    	int j = len >> 1;
    	for(int i = 1;i < len - 1;++i)
    	{
    		if(i < j) swap(F[i],F[j]);	// reverse
    		int k = len>>1; 
    		while(j>=k)
    		{
    			j -= k;
    			k >>= 1;
    		}
    		if(j < k) j += k;
    	}
    }
    
    void FFT(Complex F[],int len,int t)
    {
    	rader(F,len);
    	for(int h=2;h<=len;h<<=1)
    	{
    		Complex wn(cos(-t*2*pi/h),sin(-t*2*pi/h));
    		for(int j=0;j<len;j+=h)
    		{
    			Complex E(1,0);	//旋转因子
    			for(int k=j;k<j+h/2;++k)
    			{
    				Complex u = F[k];
    				Complex v = E*F[k+h/2];
    				F[k] = u+v;
    				F[k+h/2] = u-v;
    				E=E*wn;
    			}
    		}
    	}
    	if(t==-1)	//IDFT
    		for(int i=0;i<len;++i)
    			F[i].r/=len;
    }
    
    void Conv(Complex a[],Complex b[],int len) //求卷积
    {
    	FFT(a,len,1);
    	FFT(b,len,1);
    	for(int i=0;i<len;++i) a[i] = a[i]*b[i]; 
    	FFT(a,len,-1);
    }
    
    void init(char *s1,char *s2)
    {
    	int n1 = strlen(s1),n2 = strlen(s2);
    	len = 1;
    	while(len < 2*n1 || len < 2*n2) len <<= 1;
    	int i;
    	for(i=0;i<n1;++i)
    	{
    		va[i].r = s1[n1-i-1]-'0';
    		va[i].i = 0;
    	}
    	while(i<len)
    	{
    		va[i].r = va[i].i = 0;
    		++i;
    	}
    	for(i=0;i<n2;++i)
    	{
    		vb[i].r = s2[n2-i-1]-'0';
    		vb[i].i = 0;
    	}
    	while(i<len)
    	{
    		vb[i].r = vb[i].i = 0;
    		++i;
    	}
    }
    
    void gao()
    {
    	Conv(va,vb,len);
    	memset(res,0,sizeof res);
    	for(int i=0;i<len;++i)
    	{
    		res[i]=va[i].r + 0.5;
    	}
    	for(int i=0;i<len;++i)
    	{
    		res[i+1]+=res[i]/10;
    		res[i]%=10;
    	}
    	int high = 0;
    	for(int i=len-1;i>=0;--i)	
    	{
    		if(res[i])	
    		{
    			high = i;
    			break;
    		}
    	}
    	for(int i=high;i>=0;--i) putchar('0'+res[i]);
    	puts("");
    }
    
    
    int main()
    {
    	while(scanf("%s %s",s1,s2)==2)
    	{
    		init(s1,s2);
    		gao();
    	}
    	return 0;
    }
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  • 原文地址:https://www.cnblogs.com/qscqesze/p/5379641.html
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