• dij 费用流


    #include <bits/stdc++.h>
    using namespace std;
    typedef long long lld;
    const int MAXN = 50010, MAXM = 1000010, INF = 0x3f3f3f3f;
    struct Edge { int to, next, cap, flow, cost; } edge[MAXM];
    int head[MAXN], tol, pre[MAXN], dis[MAXN], h[MAXN];
    struct Node { int x, dis; bool operator<(Node b) const { return b.dis < dis; } };
    priority_queue<Node> Q;
    
    void init() {
    	tol = 0; memset(head, -1, sizeof(head));
    }
    
    void addedge(int u, int v, int cap, int cost) {
    	edge[tol] = (Edge){ v, head[u], cap, 0, cost }; head[u] = tol++;
    	edge[tol] = (Edge){ u, head[v], 0, 0, -cost }; head[v] = tol++;
    }
    
    bool dijkstra(int s, int t, int N) {
        for (int i = 0; i <= N; i++)
            h[i] = min(h[i] + dis[i], INF), dis[i] = INF, pre[i] = -1;
        dis[s] = 0, Q.push(Node { s, 0 });
        while (!Q.empty()) {
            int u = Q.top().x, dist = Q.top().dis; Q.pop();
            if (dist > dis[u]) continue;
            for (int i = head[u]; ~i; i = edge[i].next) {
                Edge& e = edge[i]; int v = edge[i].to;
                if (e.cap > e.flow && dis[v] > dis[u] + e.cost + h[u] - h[v]) {
                    dis[v] = dis[u] + e.cost + h[u] - h[v], pre[v] = i;
                    Q.push(Node { v, dis[v] });
                }
            }
        }
        return dis[t] < INF;
    }
    
    pair<int,int> minCostMaxFlow(int s, int t, int N) {
    	int flow = 0, cost = 0;
    	while (dijkstra(s, t, N)) {
    		int Min = INF, Fee = dis[t] + h[t] - h[s];
    		for (int i = pre[t]; ~i; i = pre[edge[i^1].to])
    			Min = min(Min, edge[i].cap - edge[i].flow);
    		for (int i = pre[t]; ~i; i = pre[edge[i^1].to])
    			edge[i].flow += Min, edge[i^1].flow -= Min;
    		flow += Min, cost += Fee * Min;
    	}
    	return make_pair(flow, cost);
    }
    
    int main()
    {
        init(); int n, m, s, t, u, v, w, f;
        scanf("%d %d %d %d", &n, &m, &s, &t);
        for (int i = 1; i <= m; i++)
            scanf("%d %d %d %d", &u, &v, &w, &f),
            addedge(u, v, w, f);
        auto ans = minCostMaxFlow(s, t, n);
        printf("%d %d
    ", ans.first, ans.second);
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/luowentao/p/11683531.html
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