QT绘制心形图案二

本来打算用绘制贝塞尔曲线的方法绘制心形，可是本数学渣怎么都搞不定那几个控制点坐标。研究了一上午，通过lineTo方法，最终还是绘制出封闭的心形图。还收获了意外的效果。

看来就差个女朋友，给她看了。

代码如下：

.h文件

#pragma once

#include <QtWidgets/QDialog>
#include "ui_heart.h"
#include <Qpainter>
class Heart : public QDialog
{
    Q_OBJECT
public:
    Heart(QWidget *parent = Q_NULLPTR);
protected:
    void paintEvent(QPaintEvent *);
private:
    Ui::HeartClass ui;
};

.cpp文件

#include "heart.h"

Heart::Heart(QWidget *parent): QDialog(parent)
{
    ui.setupUi(this);
}

void Heart::paintEvent(QPaintEvent *event)
{
    double k = 10;
    QPainter painter(this);
    painter.setRenderHint(QPainter::Antialiasing, true);
    QColor my_color(237, 162, 255, 255);
    QBrush my_brush(my_color);
    painter.setPen(Qt::red);
    /*painter.setBrush(my_brush);*/
    painter.translate(this->width()/2, this->height()/2);
    QPainterPath polygonPath;
    polygonPath.setFillRule(Qt::WindingFill);
    float x = 16 * k * sin(0.0)*sin(0.0)*sin(0.0);
    float y = 13 * k * cos(0.0) - 5 * k*cos(0.0) - 2 * k*cos(0.0) - cos(0.0);
    polygonPath.moveTo(x, -y);
    for (double t = 0.01; t < 100; t += 0.05)
    {
        x = 16 * k * sin(k*t)*sin(k*t)*sin(k*t);
        y = 13 * k * cos(k*t) - 5 * k * cos(2 * k * t) - 2 * k * cos(3 * k * t) - cos(4 * k * t);
        polygonPath.lineTo(x, -y);
        /*painter.drawPoint(x,-y);
        painter.drawLine(0,0,x,-y);    
        painter.drawLine(0,0,x+100,-y);*/    
    }
    painter.drawPath(polygonPath);
}

效果图