• Partition分组使用和行列转换


    CREATE TABLE score
    (
    name NVARCHAR(20),
    subject NVARCHAR(20),
    score INT
    )
    --2.插入测试数据
    INSERT INTO score(name,subject,score) VALUES('张三','语文',98)
    INSERT INTO score(name,subject,score) VALUES('张三','数学',80)
    INSERT INTO score(name,subject,score) VALUES('张三','英语',90)
    INSERT INTO score(name,subject,score) VALUES('李四','语文',88)
    INSERT INTO score(name,subject,score) VALUES('李四','数学',86)
    INSERT INTO score(name,subject,score) VALUES('李四','英语',88)
    INSERT INTO score(name,subject,score) VALUES('李明','语文',60)
    INSERT INTO score(name,subject,score) VALUES('李明','数学',86)
    INSERT INTO score(name,subject,score) VALUES('李明','英语',88)
    INSERT INTO score(name,subject,score) VALUES('林风','语文',74)
    INSERT INTO score(name,subject,score) VALUES('林风','数学',99)
    INSERT INTO score(name,subject,score) VALUES('林风','英语',59)
    INSERT INTO score(name,subject,score) VALUES('严明','英语',96)

    select * from score

    select subject from score   for xml path('')
    SELECT Subject+','  FROM score
        where name='林风'
      FOR XML PATH('')
     
       SELECT  cast(score as varchar)+',' FROM score
        where name='林风'
      FOR XML PATH('')
     
    SELECT name ,sum(score),
    (SELECT Subject+',' FROM score
      WHERE name=A.name
      FOR XML PATH('')) AS StuList,
     
     
      (SELECT cast(score as varchar(10))+',' FROM score
      WHERE name=A.name
      FOR XML PATH('')) AS StuList
     
     
    FROM score A
    GROUP BY name

    --3.取每个学科的前3名数据

    SELECT * FROM
    (
    SELECT subject,name,score,ROW_NUMBER() OVER(PARTITION BY subject ORDER BY score DESC) AS num FROM score
    ) T WHERE T.num <= 3 ORDER BY subject
    --------------------------------------
    SELECT * FROM
    (
    SELECT subject,name,score,Rank() OVER(PARTITION BY subject ORDER BY score DESC) AS num FROM score
    ) T WHERE T.num <= 3 ORDER BY subject
    -----------------------------------------------

    SELECT * FROM
    (
    SELECT subject,name,score,Dense_Rank() OVER(PARTITION BY subject ORDER BY score DESC) AS num FROM score
    ) T WHERE T.num <= 3 ORDER BY subject
    -----------------------------------------------
    /*以下是我对4个排名函数的类比表格:         
                   排名连续性   排名并列性         
    RANK()        不一定连续    有并列         
    DENSE_RANK()   连续         有并列         
    ROW_NUMBER()   连续         无并列         
    NTILE()        连续         有并列         
    */

    --4行转列

    SELECT name,ISNULL([数学],0) [数学],ISNULL([英语],0) [英语],ISNULL([语文],0) [语文]
    FROM score PIVOT (max(score) FOR subject IN ([数学],[英语],[语文]) ) AS pt

    SELECT name,ISNULL([数学],0) [数学],ISNULL([英语],0) [英语]
    FROM score PIVOT (max(score) FOR subject IN ([数学],[英语]) ) AS pt


    SELECT Name AS 姓名 ,
         MAX(CASE Subject WHEN '数学' THEN score ELSE 0 END) [数学] ,
         MAX(CASE Subject WHEN '英语' THEN score ELSE 0 END) [英语] ,
         MAX(CASE Subject WHEN '语文'  THEN score ELSE 0 END) [语文]
       FROM score GROUP BY name

    --5动态行转列
    declare @sql varchar(8000)
    --set @sql = 'select Name as ' + '姓名'
    set @sql=''
    select @sql = @sql+ ' , max(case Subject when ''' + Subject + ''' then score else 0 end) [' + Subject + ']'
    from (select distinct Subject from score) as a
    --set @sql = @sql + ' from score group by name'
    print @sql
    exec(@sql)

    --6 动态Pivot
    declare @sql varchar(500)
    declare @sql2 varchar(500)
    select @sql2=  isnull(@sql2 + ',' , '') + 'isnull(['+Subject+'],0) as '+Subject+'' from score group by Subject
    select @sql = isnull(@sql + ',' , '') + '['+Subject+']' from score group by Subject
    print @sql
    print @sql2
    exec ('select Name,'+@sql2+' from (
    select Name,s.Score,Subject from score s
     
    ) a pivot (sum(Score) for Subject in (' + @sql + ')) b')

       
    SELECT name,sum(score) score,
    (SELECT Subject+',' FROM score
      WHERE name=A.name
      FOR XML PATH('')) AS StuList,
      (SELECT cast(score as varchar(10))+',' FROM score
      WHERE name=A.name
      FOR XML PATH('')) AS StuList
    FROM score A
    GROUP BY name

     

    --7 XML PATH
       select b.name,b.score,
       LEFT(b.StuList,LEN(b.StuList)-1) StuList,
       LEFT(b.ScoreList,LEN(b.ScoreList)-1) ScoreList
        from (
        SELECT name,sum(score) score,
    (SELECT Subject+',' FROM score
      WHERE name=A.name
      FOR XML PATH('')) AS StuList,
      (SELECT cast(score as varchar(10))+',' FROM score
      WHERE name=A.name
      FOR XML PATH('')) AS ScoreList
    FROM score A
    GROUP BY name ) b  order by score desc
      





      
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  • 原文地址:https://www.cnblogs.com/lijunhao/p/5950724.html
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